Jade only need 3 1/4 cans of paint

If 1200 cm^2 of material is available to make a box with a square base and an open top find the largest possible volume of the b

strojnjashka [21]

Surface area of box=1200 cm²
Volume of box=s²h 
s = side of square base 
h = height of box 
S.A. = s² + 4sh 
S.A. = surface area or 1200 cm², s²
= the square base, and 4sh = the four 'walls' of the box. 
1200 = s² + 4sh 
1200 - s² = 4sh 
(1200 - s²)/(4s) = h 

v(s) = s²((1200 - s²)/(4s)) 
v(s) = s(1200 - s²)/4 . 
v(s) = 300s - (1/4)s^3

by derivating
v'(s) = 300 - (3/4)s² 
0 = 300 - (3/4)s² 
-300 = (-3/4)s² 
400 = s² 
s = -20 and 20. 
again derivating
v"(s) = -(3/2)s 
v"(-20) = -(3/2)(-20) 
v"(-20) = 30 
v"(20) = -(3/2)(20) 
v"(20) = -30 

v(s) = 300s - (1/4)s^3 
v(s) = 300(20) - (1/4)(20)^3 
v(s) = 6000 - (1/4)(8000) 
v = 6000 - 2000
v=4000

4 0

2 years ago

Pleaseeeeeeeeeeeeee helppppppppppp

sergeinik [125]

Answer:

Step-by-step explanation:

8) (5x + 23) + (17x - 41) = 180

22x = 198

x = 9

arc JK 5(9) + 23 = 68°

arc MJ 17(9) - 41 = 112°

arc LMK 360 - 112 = 248

9) 8x + (21x - 12) + (10x + 9) + 90 = 360

39x = 273

x = 7

arc WX 21(7) - 12 = 135°

arc YW 90 + 8(7) = 146°

arc YX 10(7) + 9 = 79°

arc VXW 360 - 8(7) = 304°

6 0

2 years ago

The lcm of 165xy and 77x 3 y is _____. 1,155x 3y 11xy 12,705x 4y 2 105x 3y

trapecia [35]

The least common multiple (LCM) can be determined by factoring out the terms first,
165xy = (3)(11)(5)(x)(y)
77x³y = (7)(11)(x)(x)(x)(y)
Copy the factors writing off the repeated factors only once,
LCM = (3)(11)(5)(x)(y)(7)(x)(x)= 1155x³y
The answer is 1155x³y (first choice)

4 0

2 years ago

Read 2 more answers

Does anyone have the answers for all?

Shkiper50 [21]

Answer and Step-by-step explanation:

1-6

a.

What you can do is plug in 6 and start by doing the first machine first, then the second. If this doesn't work, do the second machine, then the first machine.

The order that works is second machine, then first machine.

Second Machine:

y = $(6)^{2} -6$ = 36 - 6 = 30

Plug into first machine now.

First Machine:

y = $\sqrt{(30) - 5} = \sqrt{25} = 5$

We see that the result is 5.

b. If we were to do the order of second machine, then first machine, we will never get a negative result (or -5 for that matter), due to the fact that you can't algebraically square root a negative number.

However, if we were to do the order of first machine, second machine, we can get a negative number. To get -5, we plug in 6 for x in the first machine, getting an answer of 1. We plug this into the second machine, getting 1^2 - 6, which results in -5.

1-7. The absolute value of a value is the positive version of that value.

a. |54| = 54

b. $-|-7\frac{3}{5}|$ = $-7\frac{3}{5}$

c. |3| - |-1| = 3 - 1 = 2

d. |2.2 - 5.13| = |-2.93| = 2.93

1-8.

a.

_

| |

| |

| || || || || |

(5 boxes on each side)

_

| |

| |

| || || || || || |

(6 boxes on each side)

b. The amount of squares on each side of the figure increases by 1.

c. There would be 1 square, because we know that the pattern is there is 2 squares added to the next figure, 1 at each end. If we go back a figure, we take away 2 squares.

1-9.

a. -42 - 17 = -59

b. 8 - (-9) = 8 + 9 = 17

c. 8(-9) = -72

d. -42 ÷ (-7) = 6

e. -2(-3)(-4) = 6(-4) = 24

f. -18 - 7 = -25

g. $(-5)^{2}$ = 25

h. $-5^{2} = -(5)^2 = -(25)$ = -25

i. $\sqrt{49}$ = 7

1-10. x = 2 Plug 2 in for x, then solve.

a. y = 7 - 3(2) = 7 - 6 = 1

b. y = $(2)^2 -1$ = 4 - 1 = 3

c. y = $\frac{18}{2}$ = 9

#teamtrees #PAW (Plant And Water)

I hope this helps!

8 0

2 years ago

Which of the following is not an identity?

Shkiper50 [21]

A ) cos² x · 1 / sin x - 1 / sin x = - sin x
cos² x - 1 / sin x = - sin x
- sin² x / sin x = - sin x
- sin x = - sin x ( correct )
B ) sin x ( cos x / sin x + sin x / cos x ) = 1 / cos x
sin x · ( cos² x + sin²x ) / sin x cos x = 1 / cos x
sin x · 1 / sin x cos x = 1 / cos x
1 / cos x = 1 / cos x ( correct )
C ) cos² x - sin² x = 1 - 2 sin² x
1 - sin² x - sin² x = 1 - 2 sin² x
1 - 2 sin² x = 1 - 2 sin² x ( correct )
D ) 1/sin²x + 1/ cos²x = 1
cos²x + sin² x / sin² x cos² x = 1
1 / cos² x sin² x = 1
cos²x sin² x ≠ 1
Answer: D ) is not an identity.

8 0

2 years ago