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2 years ago

Help me please on this question. Thanks.

Mathematics

1 answer:

Law Incorporation [45]2 years ago

8 0

I’M sorry I don’t understand it

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How do you round 5.04

kodGreya [7K]

5.00 i think is the right way

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2 years ago

Find the valur.of BAC

Lady_Fox [76]

Answer:

X=30

The whole triangle = 180 degrees

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2 years ago

Read 2 more answers

Please help! Correct answers only please!

Marrrta [24]

Answer:

D. is your answer

Step-by-step explanation:

$V=whl=7*6.5*7=318.5unit^3$

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2 years ago

Predict what the graph of the following quadratic function will look like. (If you have a graphing calculator, you can use it to

Alex17521 [72]

Answer:

u-shaped; y-intercept (0,6); symmetrical with respect to the y-axis

Step-by-step explanation:

Given that y = 2x² + 6

The graph would be the shape of that of a parabola. It can be u shaped or n shaped depending on the value of the coefficient of a comparing with the standard equation y = ax² + bx + c. If a > 0, it is u shape and if a < 0, it is n shape.

For this question, since a > 0 it would be u shaped and the intercept can be gotten by putting x = 0.

Therefore y = 0² + 6 = 0

The intercept is at (0,6) and is symmetrical with respect to the y-axis

3 0

3 years ago

The function y = x 2 - 10x + 31 has a ____

katrin [286]

Answer:

Option B. minimum is correct for the first blank

Option C. 6 is correct for second blank.

Step-by-step explanation:

In order to find the maxima or minima of a function, we have to take the first derivative and then put it equal to zero to find the critical values.

Given function is:

$f(x) = x^2-10x+31$

Taking first derivative

$f'(x) = 2x-10$

Now the first derivative has to be put equal to zero to find the critical value

$2x-10 = 0\\2x = 10\\x = \frac{10}{2} = 5$

The function has only one critical value which is 5.

Taking 2nd derivative

$f''(x) =2$

$f''(5) = 2$

As the value of 2nd derivative is positive for the critical value 5, this means that the function has a minimum value at x = 5

The value can be found out by putting x=5 in the function

$f(5) = (5)^2-10(5)+31\\=25-50+31\\=6$

Hence,

<u>The function y = x 2 - 10x + 31 has a minimum value of 6</u>

Hence,

Option B. minimum is correct for the first blank

Option C. 6 is correct for second blank.

8 0

2 years ago