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den301095 [7]
4 years ago
5

Is 0.33 bigger than 20/60?

Mathematics
2 answers:
vovangra [49]4 years ago
8 0
Hello,

To compare, let's convert 20/60 to a decimal. The decimal form of 20/60 is 0.3333 repeating.

According to the conversion, 0.33 and the fraction 20/60 are equal.

Hope this helps!

May
miss Akunina [59]4 years ago
6 0
No its not,i think. Dont rely on my answer as much.
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Answer:

B

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Answer:

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5. Find the first, fourth, and tenth terms of the arithmetic
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The first, fourth and tenth terms of the arithmetic sequence is -6, -\frac{27}{5} and -\frac{21}{5}

Explanation:

The given rule for the arithmetic sequence is A(n)=-6+(n-1)(\frac{1}{5} )

We need to determine the first, fourth and tenth terms of the sequence.

To find the first, fourth and tenth terms, let us substitute n=1,4,10 in the general rule for the arithmetic sequence.

To find the first term, substitute n=1 in A(n)=-6+(n-1)(\frac{1}{5} ) , we get,

A(1)=-6+(1-1)(\frac{1}{5} )

A(1)=-6+(0)(\frac{1}{5} )

A(1)=-6

Thus, the first term of the arithmetic sequence is -6.

To find the fourth term, substitute n=4 in A(n)=-6+(n-1)(\frac{1}{5} ) , we get,

A(2)=-6+(4-1)(\frac{1}{5} )

A(2)=-6+(3)(\frac{1}{5} )

A(2)=\frac{-30+3}{5}

A(2)=\frac{-27}{5}

Thus, the fourth term of the arithmetic sequence is -\frac{27}{5}

To find the tenth term, substitute n=10 in A(n)=-6+(n-1)(\frac{1}{5} ) , we get,

A(10)=-6+(10-1)(\frac{1}{5} )

A(10)=-6+(9)(\frac{1}{5} )

A(10)=-6+\frac{9}{5}

A(10)=-\frac{21}{5}

Thus, the tenth term of the arithmetic sequence is -\frac{21}{5}

Hence, the first, fourth and tenth terms of the arithmetic sequence is -6, -\frac{27}{5} and -\frac{21}{5}

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