Solve. -x ≥ -3 A) x ≥ 3 B) x ≤ 1 C) x ≤ 3 D) x ≥ -3

Mathematics

1 answer:

lys-0071 [83]3 years ago

7 0

Answer:

Step-by-step explanation:

Given

- x ≥ - 3

Multiply both sides by - 1 reversing the inequality symbol as a consequence of multiplying by a negative quantity, that is

x ≤ 3 → C

You might be interested in

The length of the hypotenuse of a right triangle is 26 in. one leg measures 13 in. find the length of the other leg. round your

Ghella [55]

Use c^2=a^2+b^2
26^2= 13^2 + b^2
676=169 + b^2 (subtract 169 from both sides)
507= b^2 (take the square root of each side)
22.52 in. =b

3 0

3 years ago

14 5 18 24 15 28 34 _ what number is needed to complete the pattern

AlekseyPX

Minus 9, add 13, add 6, mus 9, add 13, add 6, minus 9 is next

34-9=25
the blank is 25

4 0

3 years ago

Help help help help help help help

MrRa [10]

The 2nd one is the answer because it shows Distributive Property which is a(b+c) or (b+c)a.

6 0

3 years ago

Read 2 more answers

Weegy if one angle of a rhombus is 35 what are the remaining three angles

Assoli18 [71]

Rhombus, opposite angles are congruent
One angle is 35 so the opposite angle will be 35 also.

Sum of interior angles in a rhombus equal 360

360 - 35 - 35 = 290

290/2 = 145 (The other two angles will be congruent)

Answer:
The remaining three angles will be 35°, 145°, 145°

7 0

3 years ago

If F(x)=4x-1 and g(x)=x^2+7, what is g(f(x))

VashaNatasha [74]

Answer

$g(f(x)) = = 16 {x}^{2} - 8x + 8$

step by step Explanation

The functions given are

$f (x)= 4x- 1$

$g(x)= {x}^{2} + 7$

We want to find:

$g(f (x))= g( 4x- 1)$

This implies that

$g(f (x))= ( (4x- 1)^{2} + 7)$

Let us now simplify

$( {a - b)}^{2} = {a}^{2} -2ab + {b}^{2}$

This implies that

$( (4x- 1)^{2} + 7) =( {(4x)}^{2} - 2(4x) \times 1 + 1$

Combine the terms to get,

$= 16 {x}^{2} - 8x + 1 + 7$

$= 16 {x}^{2} - 8x + 8$

6 0

3 years ago

Read 2 more answers