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larisa86 [58]
3 years ago
6

Every employee works 7 hours per day. every employee works 5 days per week. every employee works 49 weeks per year. how many day

s do the employee works
Mathematics
2 answers:
andriy [413]3 years ago
4 0
To determine the number of days that an employee work in a week, we simply use dimensional analysis and multiplying the number of works per week with the number of weeks in total for a year. That is,
                         employee works = (5 days per week)(49 weeks per year) 
                                                    =245 days
horsena [70]3 years ago
3 0

Answer:

245 days.

Step-by-step explanation:

It is given in the question.

Every employee works 5 days per week.

Every employee works 49 weeks per year.

We have to calculate the number of days the employee works in a year.

The number of days works in a year = 49 × 5

                                                                       = 245 days

Therefore, the total number of days the employee works would be 245 days.

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Write an expression for the 12th partial sum of the series 3/2+7/3+19/6+... using summation notation
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Answer:

S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]

S_{12}=73

Step-by-step explanation:

First\ term\ of\ the\ series(a_1)=\frac{3}{2}\\\\Second\ term\ of\ the\ series(a_2)=\frac{7}{3}\\\\Third\ term\ of\ the\ series(a_3)=\frac{19}{6}\\\\a_2-a_1=\frac{7}{3}-\frac{3}{2}=\frac{5}{6}\\\\a_3-a_2=\frac{19}{6}-\frac{7}{3}=\frac{5}{6}\\\\Hence\ it\ is\ an\ Arithmetic\ Series\ with\ first\ term=\frac{3}{2}\ and\ constant\ difference=\frac{5}{6}

a_1=\frac{3}{2}+0\times \frac{5}{6}\\\\a_2=\frac{3}{2}+1\times \frac{5}{6}\\\\a_3=\frac{3}{2}+2\times \frac{5}{6}\\\\.\\.\\.\\a_n=\frac{3}{2}+(n-1)\times \frac{5}{6}\\\\S_n=a_1+a_2+a_3+......+a_n\\\\S_n=(\frac{3}{2}+0\times \frac{5}{6})+(\frac{3}{2}+1\times \frac{5}{6})+(\frac{3}{2}+2\times \frac{5}{6})+....+(\frac{3}{2}+[n-1]\times \frac{5}{6})\\\\S_n=\sum_{i=1}^n [\frac{3}{2}+(i-1)\times \frac{5}{6}]\\\\S_n=(\frac{3}{2}+\frac{3}{2}+\frac{3}{2}+...n\ times)+\frac{5}{6}(1+2+3+4+...+(n-1))\\\\

S_n=\frac{3}{2}\times n+\frac{5}{6}\times \frac{n(n-1)}{2}\\\\

S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]

S_{12}=\frac{3}{2}\times 12+\frac{5}{6}\times \frac{(12)(12-1)}{2}\\\\S_{12}=18+55\\\\S_{12}=73

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3 years ago
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