Answer:
the function R is always 2 above on the y axis to the function G
Step-by-step explanation:
adding 2 to x makes the function go up on the y axis
Answer:
Step-by-step explanation:
Answer: 0.4512
Step-by-step explanation:
A bit string is sequence of bits (it only contains 0 and 1).
We assume that the 0 and 1 area equally likely to any place.
i.e. P(0)= P(1)= 
The length of bits : n = 10
Let X = Number of getting ones.
Then , 
Binomial distribution formula : 
, where p= probability of getting success in each event and q= probability of getting failure in each event.
Here , 
Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.
Hence, the probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.
When you are looking at a graph, a minimum point would be where the curve is decreasing, then begins to increase. Right at the point where it switches, the slope is a horizontal line, or 0. We can take the derivative is f(x), then look for all the x values where the slope (which is equal to the first derivative) is equal to zero.
f'(x) = 2 * -4sin(2x - pi)
The 2 comes from the derivative of the inside, 2x-pi.
So now set the derivative equal to 0.
-8sin(2x-pi) = 0
We can drop the -8 by dividing both sides by -8.
sin(2x-pi) = 0
This can be rewritten as arcsin(0) = 2x-pi
So when theta equals 0, what is the value of sin(theta)? At an angle of 0, there is just a horizontal line pointing to the right on the unit circle with length of 1. Sine is y/h, but there is no y value so it is just 0. If arcsin(0) = 0, we can now set 2x-pi = 0
2x = pi
x = pi/2
This is a critical number. To find the minimum value between 0 and pi, we need to find the y values for the endpoints and the critical number.
f(0) = -4
f(pi/2) = 4
f(pi) = -4
So the minimum points are at x=0 and x=pi
Answer:
7/9
Step-by-step explanation:
1 1/5 / 2 = 7/9 = 0.777
