If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
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Width = w
Length = 5w
Given,
Perimeter = 276 ft
5w * w = 276
w² = 55.2
--- w = 7.429670248402684 ≈ 7.43 ft
--- l = 5w = 5*7.43 = <span>37.14835124201342 </span>≈ 37.15 ft
I do not think we need to rewrite the first two numbers in the given above because they are already the simplest forms of themselves being whole numbers. However, the third number may be rewritten as 1/2 by dividing both numerator and denominator by 5 and the last one as 2/25 by dividing both numerator and denominator by 4.
Answer:
Below
Step-by-step explanation:
Population: 10,000
Sample: 250
Answer:
66°
Step-by-step explanation:
x+114°=180°
x+114°-114°=180°-114°
x=66°
