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AfilCa [17]
3 years ago
8

Find the mode for the following distribution. Number Frequency 16 3 20 5 24 9 28 7 32 7 36 5 40 3

Mathematics
1 answer:
andreev551 [17]3 years ago
7 0

Answer: Modes: 3, 5, 7

Step-by-step explanation:

The numbers, 3, 5, and 7, all were repeated. This gave them the total of 2 times they appeared in the sample set. Mode is the most frequent number that appears in the set, which in this case is 3, 5, and 7.

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Add. (15w - 6x) and (6x + 20w)​
Lynna [10]

Answer:

35w

Step-by-step explanation:

15w-6x+6x+20w

collect like terms

15w+20w-6x+6x

=35w

8 0
3 years ago
Triangle QRS is a right triangle.
adoni [48]
The answer is C.

∠STR = ∠SRQ = 90° (given) (A)
∠RST = ∠RSQ (common angle) (A)

By AA test for similarity,
∆STR is similar to ∆SRQ.
7 0
3 years ago
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Below is a probability distribution for the number of failures in an elementary statistics course. X 0 1 2 3 4 P(X=x) 0.41 0.18
faust18 [17]

Answer:

a) P(X=2)= 0.29

b) P(X<2)= 0.59

c) P(X≤2)= 0.88

d) P(X>2)= 0.12

e) P(X=1 or X=4)= 0.24

f) P(1≤X≤4)= 0.59

Step-by-step explanation:

a) P(X=2)= 1 - P(X=0) - P(X=1) - P(X=3) - P(X=4)= 1-0.41-0.18-0.06-0.06= 0.29

b) P(X<2)= P(X=0) + P(X=1)= 0.41 + 0.18 = 0.59

c) P(X≤2)= P(X=0) + P(X=1) + P(X=2)=0.41+0.18+0.29= 0.88

d) P(X>2)=P(X=3) + P(X=4)=0.06+0.06= 0.12

e) P(X=1 or X=4)=P(X=1 ∪ X=4) = P(X=1) + P(X=4)=0.18+0.06= 0.24

f) P(1≤X≤4)=P(X=1) + P(X=2) + P(X=3) + P(X=4)=0.18+0.29+0.06+0.06= 0.59

3 0
3 years ago
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Write the recurring decimal 0.5 as a fraction in its simplest form.​
sergejj [24]

Answer:

0.5×2/2=1/2 is the required fraction.

8 0
3 years ago
Read 2 more answers
Multiple Choice
Delvig [45]

Answer:

The answer is B

Step-by-step explanation:

The formal is A = a+b/2 time h

You just substitute the variables and get the answer

8 0
3 years ago
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