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oksian1 [2.3K]
2 years ago
9

Fernando has been saving money to buy an e-book reader. A store has just marked down the price of its readers by 40%. Each reade

r comes with a mail-in rebate for $25.
If the reader used to cost $150, what will Fernando's final price be after the markdown and rebate?

Complete each step to solve the problem.
1. How much money will Fernando save because of the 40% markdown? Show your work.
2. The total amount off includes the markdown and rebate. What is the total amount off?
3. What will the final price of the reader be? Show your work.
Mathematics
1 answer:
ikadub [295]2 years ago
4 0

Answer:

1. $90

2. $85

3. $ 149.6

Step-by-step explanation:

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160/32= 5

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Look at the histograms of real estate data and decide whether you think the standard deviation of home prices in City A was larg
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Answer:

The description according to the framework in question is illustrated in the portion below.

Step-by-step explanation:

  • These same 2 histograms are quite dissimilar or separate, for City A, each information collected has always been largely focused at 400, although for City B, these same results are interpreted at 400.
  • The price increases including its households throughout City B have quite a higher SD than those of the exchange rates throughout City A, also because documentation from City A generate a lot of price levels close to the middle of the bar chart, as well as the wages throughout City B, require a high amount of rates farther from the midpoint of the

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2 years ago
3252614683754629158741032465x93756356872264881+432757232878247-3243566=
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Answer:

bout 7

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
La potencia que se obtiene de elevar a un mismo exponente un numero racional y su opuesto es la misma verdadero o falso?
malfutka [58]

Answer:

Falso.

Step-by-step explanation:

Sea d = \frac{a}{b} un número racional, donde a, b \in \mathbb{R} y b \neq 0, su opuesto es un número real c = -\left(\frac{a}{b} \right). En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:

(a) <em>El exponente es cero.</em>

(b) <em>El exponente es un negativo impar.</em>

(c) <em>El exponente es un negativo par.</em>

(d) <em>El exponente es un positivo impar.</em>

(e) <em>El exponente es un positivo par.</em>

(a) El exponente es cero:

Toda potencia elevada a la cero es igual a uno. En consecuencia, c = d = 1. La proposición es verdadera.

(b) El exponente es un negativo impar:

Considérese las siguientes expresiones:

d' = d^{-n} y c' = c^{-n}

Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:

d' = \left(\frac{a}{b} \right)^{-n} y c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}

d' = \left(\frac{a}{b} \right)^{(-1)\cdot n} y c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}

d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}y c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}

d' = \left(\frac{b}{a} \right)^{n} y c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}

d' = \left(\frac{b}{a} \right)^{n} y c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}

d' = \left(\frac{b}{a} \right)^{n} y c' = \left[-\left(\frac{b}{a} \right)\right]^{n}

Si n es impar, entonces:

d' = \left(\frac{b}{a} \right)^{n} y c' = - \left(\frac{b}{a} \right)^{n}

Puesto que d' \neq c', la proposición es falsa.

(c) El exponente es un negativo par.

Si n es par, entonces:

d' = \left(\frac{b}{a} \right)^{n} y c' = \left(\frac{b}{a} \right)^{n}

Puesto que d' = c', la proposición es verdadera.

(d) El exponente es un positivo impar.

Considérese las siguientes expresiones:

d' = d^{n} y c' = c^{n}

d' = \left(\frac{a}{b}\right)^{n} y c' = \left[-\left(\frac{a}{b} \right)\right]^{n}

d' = \left(\frac{a}{b} \right)^{n} y c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}

d' = \left(\frac{a}{b} \right)^{n} y c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}

Si n es impar, entonces:

d' = \left(\frac{a}{b} \right)^{n} y c' = - \left(\frac{a}{b} \right)^{n}

(e) El exponente es un positivo par.

Considérese las siguientes expresiones:

d' = \left(\frac{a}{b} \right)^{n} y c' = \left(\frac{a}{b} \right)^{n}

Si n es par, entonces d' = c' y la proposición es verdadera.

Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.

3 0
3 years ago
A person places $7230 in an investment account earning an annual rate of 8.6%, compounded continuously. Using the formula V = P
ANEK [815]

Answer:

9358.07

Step-by-step explanation:

7 0
3 years ago
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