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3 years ago

Answer for brainlest

Mathematics

2 answers:

lys-0071 [83]3 years ago

7 0

Answer:

Step-by-step explanation:

angle 8 and angle 4 are called corresponding angles.so,

angle 8=angle 4

solniwko [45]3 years ago

3 0

Answer:

these are corresponding angles

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If you take a class and have three marking periods in the class and in the first period your average grade was a 85.56 the secon

Talja [164]

69.92 when you add them all up and divide it you get 69.92

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3 years ago

Please Help!! (brainliest fr best answer)

lys-0071 [83]

Answer:

1. E=75 degrees

Step-by-step explanation:

7 0

3 years ago

Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=

luda_lava [24]

Let $f(x) = x^3 - 2x - 2$ . Then differentiating, we get

$f'(x) = 3x^2 - 2$

We approximate $f(x)$ at $x_1=2$ with the tangent line,

$f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18$

The $x$ -intercept for this approximation will be our next approximation for the root,

$10x - 18 = 0 \implies x_2 = \dfrac95$

Repeat this process. Approximate $f(x)$ at $x_2 = \frac95$ .

$f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}$

Then

$\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}$

Once more. Approximate $f(x)$ at $x_3$ .

$f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}$

Then

$\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}$

Compare this to the actual root of $f(x)$ , which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.

4 0

2 years ago

The graphs show the amounts in two different bank accounts over several months.

Neko [114]

Answer:

where are the graphs?

Step-by-step explanation:

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3 years ago

-5a to the second power-7a

kakasveta [241]

-5a^2 - 7a = -a x (5a + 7)
let me know if you have any other questions
:)

7 0

3 years ago