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salantis [7]
3 years ago
7

Suppose there are three routes from North Point to Boulder Creek, four routes from Boulder Creek to Beaver Dam, four routes from

Beaver Dam to Star Lake, and two routes directly from Boulder Creek to Star Lake.
a. How many routes from North Point to Star Lake pass through Beaver Dam?
b. How many routes from North Point to Star Lake bypass Beaver Dam?
Mathematics
1 answer:
leva [86]3 years ago
5 0

Answer:

a) 48 routes

b) 6 routes.

Step-by-step explanation:

a. How many routes from North Point to Star Lake pass through Beaver Dam?

North Point -> Boulder Creek(3)

Boulder Creek -> Beaver Dam(4)

Beaver Dam -> Star Lake(4)

Multiplying:

3*4*4 = 48 routes.

b. How many routes from North Point to Star Lake bypass Beaver Dam?

North Point -> Boulder Creek(3)

Boulder Creek -> Star Lake(2)

3*2 = 6 routes.

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Answer:

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Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 13.1, \sigma = 4.1, n = 25, s = \frac{4.1}{\sqrt{25}} = 0.82

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This is the pvalue of Z when X = 11.1. So

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By the Central Limit Theorem

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3 0
4 years ago
Rounding -
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8.238; tenths\approx8.2 \\3.666; tenths\approx3.7 \\4.47; ones\approx5 \\10.86; ones\approx11 \\3.299; hundredths\approx3.30 \\20.687; hundredths\approx20.69 \\2.3654; thousandths\approx2.365\\69.0678; thousandths\approx69.068\\5.58214; hundredths\approx5.58\\468.09156; thousandths\approx468.092\\46.49; tens\approx50 \\1358.761; tens \approx1360
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