Find the co-ordinates of the mid-point of the line joining the points A(2, -5) and B(6, 9).
1 answer:
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The 2-point form of the equation of a line is
.. y = (y2 -y1)/(x2 -x1)*(x -x1) +y1
For your points (x1, y1) = (0, 3) and (x2, y2) = (3, 5), this is
.. y = (5 -3)/(3 -0)*(x -0) +3
.. y = (2/3)x +3
Written as a function, it is
.. f(x) = (2/3)x +3
.. y = (y2 -y1)/(x2 -x1)*(x -x1) +y1
For your points (x1, y1) = (0, 3) and (x2, y2) = (3, 5), this is
.. y = (5 -3)/(3 -0)*(x -0) +3
.. y = (2/3)x +3
Written as a function, it is
.. f(x) = (2/3)x +3
Answer:
∠EGF = 65°
Step-by-step explanation:
Since EF = EG the triangle is isosceles and the base angles are equal, that is
∠EGF = ∠GEF
∠EGF = =
= 65°