Question

I need the Tables and Graphs answered. I can do the Holes and Asy

Answer 1

Answer:

7.) vertical asymptote: x= -3   holes:  no holes   (graph below, table below)

8.)vertical asymptote: x= -3          hole: (2, 1/5) (graph below, table below)

9.) vertical asymptote: none          hole: (2,12) (graph below, table below)

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tep-by-step explanation:

Below are the tables/graphs

the holes/asymptotes will be solved here

7.) To solve for the vertical asymptote simplify what you can and set the denominator= 0 and solve for x

x+3=0

x= -3

8.) We can cancel out the x-2 from the numerator and denominator, set the denomiator= 0 and then solve for x

x+3=0

x= -3

Because we canceled the set of numbers there is a hole

we know that when x=2 (in the unsimplified version) the answer is undefined. To solve for the y coordinate plug in x=2 into 1/(x+3)

1/5

9.) start by factoring 3x²-12 = 3(x+2)(x-2)

same deal for the vertical asymptote (simplify what you can and set the denominator equal to 0)

cancel out the x-2 but in doing so the denominator is one and so there is no vertical asymptote

to solve for the hole plug in x=2 for 3(x+2)

get (2,12)