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Ratling [72]
2 years ago
14

4(-4x - 3) > 36 with the steps

Mathematics
2 answers:
Lena [83]2 years ago
8 0

Answer is x < -3


4(-4x-3) > 36

Expand the brackets

-16x - 12 > 36


Rearrange the inequality to get x on its own


-16x > 36 + 12


-16x > 48


Divide both sides by -16 in order to get x on its own. When dividing both sides of the inequality by a negative number, flip the inequality sign (as this is one of the laws of inequalities)


x < 48/-16


x < -3

Sergeu [11.5K]2 years ago
5 0

Answer:

x < -3

Step-by-step explanation:

Divide both sides by 4. Since 4 is positive, the inequality direction remains the same.

−4x−3> 36/4

​Divide 36 by 4 to get 9.

−4x−3>9

Add 3 to both sides.

−4x>9+3

Add 9 and 3 to get 12.

−4x>12

Divide both sides by −4. Since −4 is negative, the inequality direction is changed.

x< 12/-4

​ Divide 12 by −4 to get −3.

x < -3

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2 years ago
Bottles of a popular cola drink are supposed to contain 300 ml of cola. There is some variation from bottle to bottle because th
Ksju [112]

Answer:

We conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.

Step-by-step explanation:

We are given that Bottles of a popular cola drink are supposed to contain 300 ml of cola. The distribution of the contents is normal with standard deviation of 3 ml.

A student who suspects that the bottler is under-filling measures the contents of six bottles. The results are: 299.4, 297.7, 301.0, 298.9, 300.2, 297.0

<u><em>Let </em></u>\mu<u><em> = mean contents of cola bottles.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq  300 ml   {means that the mean contents of cola bottles is more than or equal to the advertised 300 ml}

Alternate Hypothesis, H_A : \mu < 300 ml   {means that the mean contents of cola bottles is less than the advertised 300 ml}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about the population standard deviation;

                       T.S.  = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean contents of cola bottle = \frac{\sum X}{n} = 299.03 ml

            \sigma = population standard deviation = 3 ml

            n = sample of bottles = 6

So, <em><u>test statistics</u></em>  =  \frac{299.03-300}{\frac{3}{\sqrt{6} } }     

                               =  -0.792

<em>Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is more than the critical value of z as -0.792 > -1.6449, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.

8 0
3 years ago
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