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3 years ago

Help me with this!!!

Mathematics

1 answer:

hram777 [196]3 years ago

3 0

Answer:

Yes

Step-by-step explanation:

You can use the perpendicular bisector theorem, because the bisecting line is intersecting at a right angle, which means it is actually perpendicular. Along with IJ and IH being congruent (equal)

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3 years ago

Solve for x. <br> 8x^2 - 5 = 11

GenaCL600 [577]

Answer:

x = ±sqrt(2)

Step-by-step explanation:

8x^2 - 5 = 11

Add 5 to each side

8x^2 - 5+5 = 11+5

8x^2 = 16

Divide each side by 8

8x^2 = 16/8

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5 0

4 years ago

Read 2 more answers

Calculate the area of triangle ABC with altitude, CD, given

defon

Answer:

37.5 square units

Step-by-step explanation:

Given:

A(-6,-4), B(6,5), C(-1,6), and D(2, 2), where CD is the altitude if ∆ABC

Required:

Area of ∆ABC

SOLUTION:

Area of a ∆ABC =½*AB*CD

✍️ $AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{6 -(-6))^2 + (5 -(-4))^2$

$AB = \sqrt{12^2 + 9^2}$

$AB = \sqrt{144 + 81}$

$AB = \sqrt{225} = 15$

✍️ $CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{2 -(-1))^2 + (2 - 6)^2$

$CD = \sqrt{(3)^2 + (-4)^2}$

$CD = \sqrt{9 + 16}$

$CD = \sqrt{25} = 5$

✍️Area of a ∆ABC =½*AB*CD

= ½*15*5

✅ Area = 37.5 square units

5 0

3 years ago