1.5b=11-9
1.5b=2
b=1.3 repeating or 1 1/3
Answer:
The area of one trapezoidal face of the figure is 2 square inches
Step-by-step explanation:
<u><em>The complete question is</em></u>
The point of a square pyramid is cut off, making each lateral face of the pyramid a trapezoid with the dimensions shown. What is the area of one trapezoidal face of the figure?
we know that
The area of a trapezoid is given by the formula

where
b_1 and b-2 are the parallel sides
h is the height of the trapezoid (perpendicular distance between the parallel sides)
we have

substitute the given values in the formula


Answer:
Area of equilateral triangle = 81√3 cm²
Step-by-step explanation:
Given:
Perimeter of an equilateral triangle = 54 cm
Find:
Area of equilateral triangle
Computation:
Perimeter of an equilateral triangle = 3 x Side
54 = 3 x Side
Side of equilateral triangle = 54 / 3
Side of equilateral triangle = 18 cm
Area of equilateral triangle = [√3/4]side²
Area of equilateral triangle = [√3/4][18]²
Area of equilateral triangle = [√3/4][324]
Area of equilateral triangle = [√3][81]
Area of equilateral triangle = 81√3 cm²
Answer:
49/54
Step-by-step explanation:
7/9 + 7/54
42/54 + 7/54
49/54
Answer:
c
Step-by-step explanation: