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Elis [28]
3 years ago
10

Question 1 - Part A

Mathematics
1 answer:
Vikki [24]3 years ago
3 0

Answer:

A and C

Step-by-step explanation:

Part A

150+30x, x being the amount of visits she takes

Part C

150+30(3)

150+90

240

$240

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Theorem: A line parallel to one side of a triangle divides the other two proportionately.
Kisachek [45]

Answer:

Segment BF = 16

Step-by-step explanation:

The given theorem states that a line parallel to one side of a triangle divides the other two sides proportionately

The given theorem is the Triangle Proportionality Theorem

According to the theorem, given that segment DE is parallel to segment BC, we have;

\dfrac{AD}{BD} = \dfrac{AE}{EC}

Therefore;

BD = \dfrac{AD}{\left(\dfrac{AE}{EC} \right) }  = AD \times \dfrac{EC}{AE}

Which gives;

BD = 6 \times \dfrac{18}{12}= 9

Similarly, given that EF is parallel to AB, we get;

\dfrac{AE}{EC} = \dfrac{BF}{FC}

Therefore;

BF = FC \times \dfrac{AE}{EC}

Which gives;

BF = 24 \times \dfrac{12}{18} = 16

Therefore, the statement that can be proved using the given theorem is segment BF = 16.

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Help ASAP please !! No scam I really need this<br> Trigonometry!!
USPshnik [31]
<h3>Answer:  Choice D)  7.5 cm</h3>

==========================================================

Explanation:

We are told that quadrilateral ABCD is similar to quadrilateral EFGH.

The order of the four letter sequence is important.

  • For ABCD, we have AB as the first pair of letters.
  • For EFGH, we have EF as the first pair of letters.

Therefore, AB and EF are corresponding sides.

So AB = 10 and EF = x pair up together. We can form the ratio AB/EF which becomes 10/x.

The diagram shows that AD = 8. Notice that A and D are the first and last letters of ABCD. The first and last letters of EFGH are E and H. We can see that AD and EH correspond to one another because of this.

AD = 8 and EH = 6 forming the ratio AD/EH = 8/6

Because the quadrilaterals are similar, the corresponding ratios must be the same. Therefore, AB/EF is the same as AD/EH.

-----------------------

Let's set up a proportion to solve for x

AB/EF = AD/EH

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