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lyudmila [28]
3 years ago
5

Is this correct or no Please help me

Mathematics
1 answer:
k0ka [10]3 years ago
3 0

Answer:

I got y = 10

or

y = 24

or the answer is y = -5x since the 4 stays the same but the -5x changes

I feel like you have to replace with x with the numbers

Step-by-step explanation:

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Find the area of the figure.
Anettt [7]

Answer: 28.5 square units.

Step-by-step explanation: Separate the figure into a rectangle and a triangle. Count the length and width of the rectangle. The length of the rectangle is 8 units and the width is 3 units. To find the area use the formula l*w. 8*3=24.

Next find the area of the triangle section. The triangle is 3 units tall and 3 units wide. To find the area use the formula 1/2(l*w). 3*3=9. 9/2=4.5.

Finally add the areas of the rectangular section and the triangular section. 24+4.5=28.5.

4 0
3 years ago
Help me with these math questions....
Nady [450]

Answer: cotθ

<u>Step-by-step explanation:</u>

 tanθ * cos²θ * csc²θ

=  \dfrac{sin\theta}{cos\theta} * \dfrac{cos\theta*cos\theta}{} *\dfrac{1}{sin\theta*sin\theta}

= \dfrac{cos\theta}{sin\theta}

= cotθ

Answer: B

<u>Step-by-step explanation:</u>

The parent graph is y = x²

The new graph y = -x² + 3 should have the following:

  • reflection over the x-axis
  • vertical shift up 3 units

Answers:

  • a. Quadrant II
  • b. negative
  • c. \dfrac{\pi}{6}
  • d. C
  • e.-\dfrac{\sqrt{3}}{3}

<u>Explanation:</u>

\dfrac{17\pi}{6} - \dfrac{12\pi}{6} = \dfrac{5\pi}{6}

a) Quadrant 2 is: \dfrac{\pi}{2} < \theta < \pi

b) In Quadrant 2, cos is negative and sin is positive, so tan is negative

c) \pi-\dfrac{5\pi}{6} = \dfrac{\pi}{6}

d) the reference line is above the x-axis so it is negative -->  -tan\dfrac{\pi}{6}

e) tan(\dfrac{5\pi}{6})=\dfrac{1}{-\sqrt{3}}=-\dfrac{\sqrt{3}}{3}


4 0
3 years ago
The sum of two numbers is forty-five. two times the larger number is three times the smaller number.
Kitty [74]
X+y=45
2x=3y

2(45-y)=3y
90-2y=3y
90=5y
y=18

x+y=45
x+18=45
x=27

The two numbers are 18 and 27
8 0
3 years ago
Please help me with this question
Alenkasestr [34]

Answer:

\sqrt{8 + y}

3 0
2 years ago
What is the approximate area of the shaded sector in the circle shown below?
forsale [732]

Answer:

where is the picture...

6 0
3 years ago
Read 2 more answers
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