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3 years ago

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Triangle ABC is a right triangle with legs AB and AC. Points X and Y lie on legs AB and AC, respectively, so that AX:XB=AY:YC=1:

2. If BY=16 units and CX=28 units, what is the length of the hypotenuse BC? Express your answer in simplest radical form.

1 answer:

Dafna11 [192]3 years ago

5 0

Answer:

i don't get it

Step-by-step explanation:

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A Ferris wheel is 136 feet tall. It casts a 34-foot shadow.

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Step-by-step explanation:

This problem involves using ratios to compare side lengths in similar triangles.

136/34=x/1.5

136/34*1.5=x/1.5*1.5

136/34*1.5=x

x=6

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$\frac{1}{2} x$

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3 years ago

Arrange the expressions in ascending order of their values when x=-2

alex41 [277]

<u><em>Answer:</em></u>

<u>The expressions in ascending order would be:</u>

$\frac{3x^2+1}{2(x-1)} < \frac{x^2-1}{1-2x} < \frac{x^2}{1-2x} < \frac{2x^2+x}{2}$

<u>At x = -2</u>

<u><em>Explanation:</em></u>

<u>First, we will evaluate the given expressions at x = -2</u>

<u>1- The first expression:</u>

$\frac{x^2}{1-2x}=\frac{(-2)^2}{1-2(-2)}=\frac{4}{5}$

<u>2- The second expression:</u>

$\frac{x^2-1}{1-2x}=\frac{(-2)^2-1}{1-2(-2)}=\frac{3}{5}$

<u>3- The third expression:</u>

$\frac{2x^2+x}{2}=\frac{2(-2)^2+(-2)}{2}=3$

<u>4- The fourth expression:</u>

$\frac{3x^2+1}{2(x-1)}=\frac{3(-2)^2+1}{2(-2-1)}=-\frac{13}{6}$

<u>Then, we will arrange the values in an ascending order:</u>

$-\frac{13}{6} < \frac{3}{5} < \frac{4}{5} < 3$

<u>Finally, we arrange the expressions based on the value arrangement:</u>

$\frac{3x^2+1}{2(x-1)} < \frac{x^2-1}{1-2x} < \frac{x^2}{1-2x} < \frac{2x^2+x}{2}$

Hope this helps :)

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