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Alja [10]
2 years ago
11

The side lengths of a triangle are 5,10, and 13. Is this a right Triangle?

Mathematics
1 answer:
ollegr [7]2 years ago
3 0

No because 5^2 +10^2 is not equavalent to 13^2

by using the pythagoras' theorem

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Can someone please help me with this question?!? I am so confused and I don't know how to answer it.
lbvjy [14]

9514 1404 393

Answer:

  a. f(0) = 1

  b. DNE (does not exist)

  c. DNE

  d. lim = 3

Step-by-step explanation:

The function exists at a point if it is defined there. The function is defined anywhere on the solid line and at solid dots. It is not defined at open circles. So, the function is defined everywhere except (2, 3), which has an open circle.

The open circle at (0, 4) prevents the function from being doubly-defined at x=0, since it is already defined to be 1 at x=0.

This discussion tells you ...

  f(0) = 1

 f(2) does not exist. There is a "hole" in the function definition there.

__

The function has a limit at a point if approaching from the left and approaching from the right have you approaching that same point.

Consider the point (1, 2). The graph is a solid line through that point. Approaching from values less than x=1, we get to the same point (1, 2) as when we approach from values greater than x=1.

Similarly, consider the point (2, 3). Approaching from values of x less than 2, we get to the same point (2, 3) as when we approach from x-values greater than 2. The limit at x=2 is 3. The only difference from the previous case is that the function is not actually defined to be that value there.

__

Now consider what happens at x=0. When we approach from the left, we approach the point (0, 4). When we approach from the right, we approach the point (0, 1). These are different points. Because they are different coming from the left and from the right, we say "the limit as x→0 does not exist."

__

In summary, ...

  a) f(0) = 1

  b) lim x → 0 does not exist

  c) f(2) does not exist

  d) lim x → 2 = 3

_____

<em>Additional comment</em>

The significance of the function not being defined at a point where the limit exists, (2, 3), is that <em>the function is not continuous there</em>. This kind of discontinuity is called "removable", because we could make the function continuous at x=2 by defining f(2) = 3 (that is, "filling the hole").

6 0
2 years ago
2. If the diameter of a circle is 2V10, what is the area<br> of the circle.
Sidana [21]
Area is 10pi I think Bc radius is radical 10 Bc 2 radical 10/2 is radical 10. Then we do pi times radical 10 to the second power. Radical 10 to the second power is 10 Bc we remove radical when it is to the second power. Therefore, it becomes 10 times pi or 10pi
6 0
2 years ago
Help with this question
Morgarella [4.7K]

Answer:

C) (x-3)(x+3)

Note:

Just a tip there is an app called Desmos where you can put in equations like this and it will graph them for you.

7 0
2 years ago
How do I do lesson 12 grade 6 problem set
myrzilka [38]
Umm.. I have to see the problems, we might not have the same textbooks so
8 0
2 years ago
Read 2 more answers
What is the answer to this question?
Klio2033 [76]
Hey!!!
Answer is.....


Area=
\pi {r}^{2}
3.14 \times  {15}^{2}
706.5
Answer is 706.5 cm^2...


HOPE IT HELPS YOU '_'
7 0
3 years ago
Read 2 more answers
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