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3 years ago

Math problems: Inequalities:

Mathematics

2 answers:

Alex73 [517]3 years ago

7 0

Hey Jeremy,

1. x < 4
2. b > -5
3. w > -3
4. g < -3

Hope this helps! <3

andrew-mc [135]3 years ago

4 0

1.
x+5<9
x<4

2.
b-2>-7
b>-5

3.
1>-w/3
3>-w
or w>-3

4.
6<-2g
3<-g
or g<-3

Hope this helps :)

You might be interested in

Write the equation of a line that goes through (5,3) and is parallel to the line y=2x+7

oee [108]

Answer:

y = 2x - 7

Step-by-step explanation:

Parallel lines have the same slope, so the line will also have a slope of 2

Plug in the slope and given point into y = mx + b to solve for b:

y = mx + b

3 = 2(5) + b

3 = 10 + b

-7 = b

Then, plug in the slope and b into y = mx + b

y = 2x - 7 is the equation of the line

8 0

3 years ago

Which value is equivalent to

Ksenya-84 [330]

Answer:

$\frac{25}{144}$

Step-by-step explanation:

$(\frac{7 * 5 * 2}{7 * 3} )^2 * (\frac{5^0}{2^-3})^3 * 2^{-9}$

Simplified becomes;

$(\frac{10}{3})^2 * 2^3 * \frac{1}{2^9}$

Simplifying further gives; $\frac{25}{144}$

6 0

3 years ago

41. Assuming that a man can complete the work alone in x days, his work in four days would be: a) b) X X C d) 4x x 42. If a man

Schach [20]

Percentage and ratio word problems require understanding of the relationship between variables from which the question is formed

The options that give the correct values of the duration of the work are;

$41. \ c) \ \dfrac{4}{x}$

$42. \ d) \ \dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

43. a) 35 days

44. c) 21·a + 28·b = 1

45. c) (42, 56)

Reasons:

41. Number of days it takes a man to complete the work alone = x days

Therefore;

$The \ work \ done \ by \ the \ man \ in \ one \ day = \dfrac{1}{x}$

$The \ work \ done \ in \ four \ days \ by\ the \ man = 4 \times \dfrac{1}{x} = \dfrac{4}{x}$

The correct option is $c) \ \dfrac{4}{x}$

42. Number of days it takes a man to complete the work alone = x days

$Work \ done \ by \ a\ man \ in \ one \ day = \dfrac{1}{x}$

$Work \ done \ by \ four \ men \ in \ one \ day = \dfrac{4}{x}$

Number of days it takes a boy to complete the work alone = y days

$Work \ done \ by \ a \ boy \ in \ one \ day = \dfrac{1}{x}$

$Work \ done \ by \ six \ boys \ in \ one \ day = \dfrac{6}{y}$

4 men and 6 boys work for 5 days to complete the work

Therefore, work done by 4 men and 6 boys in 1 day is therefore;

$\dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

The correct option is therefore;

$d) \ \dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

43. As per the case study, we have;

Case 1

$\dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

Which gives;

$\dfrac{6\cdot x + 4\cdot y}{y \cdot x} = \dfrac{1}{5}$

30·x + 20·y = y·x

Case 2

$\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$

Which gives;

$\dfrac{4\cdot x + 3\cdot y}{y \cdot x} = \dfrac{1}{7}$

28·x + 21·y = y·x

Therefore;

30·x + 20·y = 28·x + 21·y

∴ 2·x = y

Plugging in the value of y = 2·x, in Case 1 gives;

$\dfrac{4}{x} + \dfrac{6}{2 \cdot x} = \dfrac{1}{5}$

$\dfrac{2 \times 4 + 6}{2 \times x} = \dfrac{14}{2 \times x} =\dfrac{7}{x} = \dfrac{1}{5}$

7 × 5 = x

x = 7 × 5 = 35

The number of days, x, it takes a man to complete the work alone, is given by option; a) 35 days

44. For the equation $\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$ , if $a = \dfrac{1}{x}$ , and $b = \dfrac{1}{y}$ , we have;

$3 \cdot a+ 4\cdot y = \dfrac{1}{7}$

21·a + 28·y = 1

The correct option is option C. 21·a + 28·b = 1

45. A solution to the equation $\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$ , is given by the values of x, and y, that gives;

$\dfrac{1}{14} + \dfrac{1}{14} = \dfrac{1}{7}$

We have;

3 × 14 = 42

4 × 14 = 56

Therefore, a solution to the equation is (42, 56)

The correct option is $c) \ \underline{ (42, \ 56)}$

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3 0

2 years ago

You would also like your room painted

torisob [31]

Answer:

2 hours

Step-by-step explanation:

300/25 = 12 12 x 10 = 120 minutes = 2 hours

Hope this helped! If it did, please give me brainliest, it would help a lot! Thanks! :D

3 0

3 years ago

For parallelogram LMNO , if m

natali 33 [55]

I'm just going to assume you're given the volume and LMNO are sides of the parallelogram

Area = LMNO

M=?

M= $\frac{area}{LNO}$

5 0

3 years ago