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Margaret [11]
2 years ago
10

Anyone know this ion get it ??

Mathematics
1 answer:
ehidna [41]2 years ago
5 0

Answer:

D.

Step-by-step explanation:

So the question is asking which set of inequalities and given point represent the graph. The point it gives is (-3,1) on the graph. That already narrows your choices down to B and D. Now, the easiest way to see the answer is look at the y axis. In the equation y=mx+b, b is the value on the y axis. We see on the y axis that the equations pass through positive 1 and 2. D adds 1 and 2 the equations, so it would produce that graph.

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What is the midpoint of the segment shown below (-8,-7) (-7,-8)
svetlana [45]
Given two points (x₁,y₁) and (x₂,y₂) the midpoint would be:
M=((x₁+x₂)/2 , (y₁+y₂)/2)

In this case, the points would be: (-8,-7) and (-7,-8); therefore:
M=((-8-7)/2 , (-7-8)/2)=(-15/2,-15/2)

Answer: C.)  (-15/2 , -15,2)
6 0
3 years ago
A bag contains 5 blue marbles, 2 green marbles, and 3 yellow marbles. What is the probability of choosing one green marble and t
Vesna [10]

Answer:

Step-by-step explanation:

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Notice (and this is important) that the denominator didn't change. Why?

Because you replaced the first marble into the bag. That word replacement is critical in a problem of this nature. There is the term non replacement which means that the second draw would have a denominator of 9.

So what is the probability of P(green then yellow)?

P(green then yellow) = 3/10 * 2/10 = 6/100

Answer: P(green then yellow) = 3/50 because 6 / 100 reduces.

4 0
2 years ago
Your company estimates that it takes you 20 minutes less each day to complete your filing tasks
Lady bird [3.3K]
Multiply the number of days by the amount of time you save each week.
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25/8 as a mixed number
Zinaida [17]
<span><span>If you would like to write 25/8 as a mixed number, you can do this using the following step:</span><span>

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3 0
3 years ago
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Which of these properties is enough to prove that a given parallelogram is also a Rectangle?
lozanna [386]

we are supposed to find

Which of these properties is enough to prove that a given parallelogram is also a Rectangle?

As we know from the theorem, if the diagonals of a parallelogram are congruent then the parallelogram is a rectangle.

The other options The diagonals bisect each other is not sufficient because in parallelogram diagonals always gets bisected , parallelogram becomes rectangles only if both the diagonals are of same length.

In a parallelogram The opposite angles and opposite sides are always equal.

Hence the correct option is

The diagonals are congruent.

3 0
3 years ago
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