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3 years ago

Anyone know this ion get it ??

Mathematics

1 answer:

ehidna [41]3 years ago

5 0

Answer:

Step-by-step explanation:

So the question is asking which set of inequalities and given point represent the graph. The point it gives is (-3,1) on the graph. That already narrows your choices down to B and D. Now, the easiest way to see the answer is look at the y axis. In the equation y=mx+b, b is the value on the y axis. We see on the y axis that the equations pass through positive 1 and 2. D adds 1 and 2 the equations, so it would produce that graph.

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The graph shows the location of point P and point R. Point R is on the y-axis and has the same y-coordinate as point P. Point Q

Mumz [18]

Answer:

n = 5

Step-by-step explanation:

Coordinate of P = (n,3)

R is on y-axis & the y-coordinate of P & R are equal. So coordinate of R = (3,0)

Coordinate of Q = (n,-2)

Using distance formula,

Distance between P & Q =

$\sqrt{ {( n - n}) ^{2} + {( 3- ( - 2) })^{2} }$

$= > \sqrt{ {(3 + 2)}^{2} } = \sqrt{ {5}^{2} } = 5$

Distance between P & R =

$\sqrt{ {(n - 0)}^{2} + {(3 - 3)}^{2} }$

$= > \sqrt{ {n}^{2} } = n$

But in question it is given that distance between P & Q is equal to the distance between P & R. So,

$n = 5$

8 0

3 years ago

I feel like something is wrong, is there?

Phoenix [80]

Answer:

# 4 (-5,2) should be placed one more place to the right

#5 (5,1) should be moved once up

Step-by-step explanation:

8 0

3 years ago

penny owes her uncle a dollar. She then borrows 4 more dollars from her uncle, but eventually pays him back 3 dollars. How much

alisha [4.7K]

So she starts out with -1 dollars. Then she borrows 4 more and gets to -5 dollars. If she pays him back 3 dollars, she is left still owing him 2 dollars as her balance is at -2 dollars.

-1 - 4 + 3 = x

X = -2

4 0

3 years ago

Read 2 more answers

Help and I’ll give brainlest answer

ollegr [7]

The answer is -88

When you multiply and then divide

7 0

3 years ago

Can someone help please!!

Tpy6a [65]

Answer:

Step-by-step explanation: