Find an equation for a line
perpendicular to y= 3x – 5 , with a y-
intercept of -2
1 answer:
Answer:
Since the lines are Perpendicular..
The Product of their Gradients = -1
m'm"=-1
m' from y=3x - 5 is 3
3.m" = -1
m" = -1/3.
Since Intercept on y axis = -2...
That of x at that point is =0
y-y' = m"(x-x")
y-(-2) = -1/3( x - 0)
y+2 = -1/3(x)
Multiplying through by 3
3y + 6 = -x
3y + x = -6. This is your Equation
To verify this.
Let's turn it into the Intercept form which is
x/a + y/b = 1
To get 1 at the right hand side... Divide through by -6
3y/-6 + x/-6 = 1
y/-2 - x/6 = 1
You could see directly below y is its intercept and thats -2
You might be interested in
4/5 ,8/10, 16/20,
You multiply both numbers with the same number.
For ex. 4×2=8 5×2=10 so we have 8/10
Answer:
A
Step-by-step explanation:
A is the only answer with ordered pairs that have a consistent rate of change, -1/3
Mult 2 by x you'll get 2x then 2 by 3 you'll get 6 and add 6 to 5, after that you'll get 11 it should look like this 2x+11.
Answer:
a= k/4+9b
Step-by-step explanation:
hope this helps, if not let me know!
Ok first we can split it in two :
and
.
The derivative of
is 3.
For the first part, we use the chain rule :
![[f(g(x))]'=g'(x)f'(g(x))](https://tex.z-dn.net/?f=%5Bf%28g%28x%29%29%5D%27%3Dg%27%28x%29f%27%28g%28x%29%29)
hence
(since the derivative of the exponential is itself) hence
