Answer:
x=2
Step-by-step explanation:
To solve, we need to isolate the variable, x
5x-18=2(3x-12) +4
Distribute the 2
5x-18=2*3x + 2*-12 +4
5x-18=6x-24+4
Combine like terms (add -24 and 4)
5x-18=6x-20
Add 18 to both sides
5x=6x-2
Subtract 6x from both sides
-x=-2
Divide both sides by -1
x=2
You want to multiply together the number of possible choices for each digit in the code.
0-9 is ten possible numbers, since repetitions are allowed (example code 2,2,2,2) there are ten possible choices per digit in the code.
10*10*10*10 = 10,000 four digit coded possible
Answer: 0.2643
Step-by-step explanation:
Given : The proportion of adults are unemployed : p=0.077
The sample size = 300
By suing normal approximation to the binomial , we have


Now, using formula
, the z-value corresponding to 26 will be :-

Using standard distribution table for z , we have
P-value=

Hence, the probability that at least 26 in the sample are unemployed =0.2643
Between 0 and 1, add dashes so you have a total of 6 marks including 0 and 1. Then count 3 over and that would be 3/5.