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AlexFokin [52]
3 years ago
13

Please answer this question, thx :)

Mathematics
1 answer:
dusya [7]3 years ago
3 0

Answer:

49.5

Step-by-step explanation:

just put into you calculator

47+(15/3)/2

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Find the distance between the points (4/4,1/10) and (2/5,7/10)​
snow_tiger [21]

Answer:

d= 2345.67

Step-by-step explanation:

 or d= 18400

6 0
3 years ago
Is this adjacent, vertical, linear, or complimentary?
Varvara68 [4.7K]
<h3>Answer: Adjacent</h3>

Adjacent angles share a common side. Think of two neighboring adjacent apartments that share a common wall.

4 0
2 years ago
Read 2 more answers
What is the range of the function f(x) = -|X - 4| + 5?
Law Incorporation [45]

Answer:

Range = (-<em>∞, 5</em>)

Step-by-step explanation:

This is the absolute value function with transformation.

The parent function is f(x) = |x|

This function has a "negative" in front, so it makes it reflect about x axis

The -4 after x makes horizontal translation of 4 units right

the +5 at the end makes the function translate 5 units UP

<em>The graph is shown in the attached picture.</em>

<em>Looking at the graph, we can clearly see the range. The range is the allowed y-values. Hence, we can see that the </em><em>range is  -infinity to 5</em>

<em />

<em>answer is not properly given, so i can't choose from the options, but the answer is -∞, 5 to 5</em>

3 0
3 years ago
Please help me 33/2 + 3y/5 = 7y/10 + 15
8090 [49]

We are given with an equation in <em>variable y</em> and we need to solve for <em>y</em> . So , now let's start !!!

We are given with ;

{:\implies \quad \sf \dfrac{33}{2}+\dfrac{3y}{5}=\dfrac{7y}{10}+15}

Take LCM on both sides :

{:\implies \quad \sf \dfrac{165+6y}{10}=\dfrac{7y+150}{10}}

<em>Multiplying</em> both sides by <em>10</em> ;

{:\implies \quad \sf \cancel{10}\times \dfrac{165+6y}{\cancel{10}}=\cancel{10}\times \dfrac{7y+150}{\cancel{10}}}

{:\implies \quad \sf 165+6y=7y+150}

Can be <em>further written</em> as ;

{:\implies \quad \sf 7y+150=165+6y}

Transposing <em>6y </em>to<em> LHS</em> and <em>150</em> to<em> RHS </em>

{:\implies \quad \sf 7y-6y=165-150}

{:\implies \quad \bf \therefore \quad \underline{\underline{y=15}}}

8 0
2 years ago
What is the domain of the function in the graph above?​
alexdok [17]

Answer: [-1,infinity)

Step-by-step explanation:

4 0
3 years ago
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