9 + 10=21 :)
9=3 x3
10= 2 x 5
3x5=15
3x2=6
15 + 6 = 21 :)
Answer:
d. 15
Step-by-step explanation:
Putting the values in the shift 2 function
X1 + X2 ≥ 15
where x1= 13, and x2=2
13+12≥ 15
15≥ 15
At least 15 workers must be assigned to the shift 2.
The LP model questions require that the constraints are satisfied.
The constraint for the shift 2 is that the number of workers must be equal or greater than 15
This can be solved using other constraint functions e.g
Putting X4= 0 in
X1 + X4 ≥ 12
gives
X1 ≥ 12
Now Putting the value X1 ≥ 12 in shift 2 constraint
X1 + X2 ≥ 15
12+ 2≥ 15
14 ≥ 15
this does not satisfy the condition so this is wrong.
Now from
X2 + X3 ≥ 16
Putting X3= 14
X2 + 14 ≥ 16
gives
X2 ≥ 2
Putting these in the shift 2
X1 + X2 ≥ 15
13+2 ≥ 15
15 ≥ 15
Which gives the same result as above.
Answer:
Step-by-step explanation:
4) x² - 14x + 48
We would find two numbers such that their sum or difference is -14x and their product is 48x².
The two numbers are - 6x and - 8x. Therefore,
x² - 6x - 8x + 48
x(x - 6) - 8(x - 6)
(x - 8)(x - 6)
5) 2x² + 21x - 11
We would find two numbers such that their sum or difference is 21x and their product is - 22x².
The two numbers are 22x and - x. Therefore,
2x² + 22x - x - 11
2x(x + 11) - 1(x + 11)
(2x - 1)(x + 11)
6) 5a² - 125
5 is a common factor. So we would factorize 5. It becomes
5(a² - 25)
Simplifying further, it becomes
5(a + 5)(a - 5)
Answer:
The cat should receive 1/5 of the can of food at each meal.
Step-by-step explanation:
Given that a cat is to receive 90 kcal of a canned food at each meal, and the food has a caloric density of 450 kcal per can, to determine what fraction of a can it should receive at each meal, the following calculation must be performed:
1 / (450/90) = X
1/5 = X
Thus, the cat should receive 1/5 of the can of food at each meal.
Answer:
No it's not!
Step-by-step explanation:
because the length (long) of J and K are totally different whereas the breadth(width) of J and K is also different which does make similar in sense
