Answer:
The vertex of the parabola is;
([-1], [3])
Step-by-step explanation:
The given quadratic equation is presented as follows;
x² + 8·y + 2·x - 23 = 0
The equation of the parabola in vertex form is presented as follows;
y = a·(x - h)² + k
Where;
(h, k) = The vertex of the parabola
Therefore, we have;
x² + 8·y + 2·x - 23 = 0
8·y = -x² - 2·x + 23
y = 1/8·(-x² - 2·x + 23)
y = -1/8·(x² + 2·x - 23)
y = -1/8·(x² + 2·x + 1 - 23 - 1) = -1/8·(x² + 2·x + 1 - 24)
y = -1/8·((x + 1)² - 24) = -1/8·(x + 1)² + 3
Therefore, the equation of the parabola in vertex form is y = -1/8·(x + 1)² + 3
Comparing with y = a·(x - h)² + k, we have;
a = -1/8, h = -1, and k = 3
Therefore, the vertex of the parabola, (h, k) = (-1, 3).
8 nickels
6 nickels, 1 dime
4 nickels, 2 dimes
2 nickels, 3 dimes
4 dimes
1 quarter, 1 nickel, 1 dime
6 different ways
Circumference = 2π x radius, so
<span>11 = 2π x radius, from which radius = 11 / 2π </span>
<span>Next, area = π x r^2 = π x (11 / 2π)^2 = 11 / 4π sq inches</span>
The square root of 128 is 11.3