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Reil [10]
2 years ago
5

A figure has been dilated from the origin by a scale factor of

Mathematics
1 answer:
Darya [45]2 years ago
6 0

Answer:

See Explanation

Step-by-step explanation:

The question has missing details. So, I'll solve using a general assumption.

Let one of the coordinates of the figure be

A = (x,y)

Let the scale factor be n

When dilated, the new figure is:

A' = n * A

A' = n * (x,y)

To return the image back to the original figure, the new scale factor mus be a reciprocal of the previous scale factor i.e. \frac{1}{n}

So:

A = A' * \frac{1}{n}

Substitute n(x,y) for A';

A = n(x,y) * \frac{1}{n}

A = \frac{n(x,y)}{n}

A = (x,y)

Take for instance:

A = (2,3)

n = 2 -- scale factor

A' = n * A

A' = 2 * (2,3)

A' = (4,6)

To get A from A', using the analysis above

A = \frac{1}{2} * (4,6)

A = (2,3)

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Answer:

6 x 7 and 42

Step-by-step explanation:

4 + 2 x 7

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2 years ago
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DIA [1.3K]

<u>c) 3, 6, 9 12</u>  is NOT a geometric progression

<h3>Further explanation </h3>

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or can be interpreted:

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The sequence can be:

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Can be formulated

\large {\boxed {\bold x_n = ar ^ {n-1}}}

where:

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b. \dfrac{8}{4}=\dfrac{16}{8}=2\to \rm geometric\:progression

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<h3>Learn more </h3>

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