3 1/2+ 5 3/8 can you solve please

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

8 0

Answer:

71/8

8.875

8 7/8

Step-by-step explanation:

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Mikes favorite peaches are $2.50 per pound at the local farmers market. She bought 13.5 pounds. how much did she spend?

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2.50*13.5=33.75. She spent $33.75.

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3 years ago

A number line goes from negative 5 to positive 5. Point D is at negative 4 and point E is at positive 5. A line is drawn from po

Ronch [10]

Directed numbers are numbers that have either a positive or negative sign, which can be shown on a number line. Therefore, point F is Fifteen-halves of line segment DE.

A number line is a system that can show the positions of positive or negative numbers. It has its ends ranging from negative infinity to positive infinity. Thus any directed number can be located on the line.

Directed numbers are numbers with either a negative or positive sign, which shows their direction with respect to the number line.

In the given question, the distance between points D and E is 9 units. So that dividing 9 units in the ratio of 5 to 6, we have;

$\frac{5}{6}$ x 9 = $\frac{45}{6}$

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Therefore, the location of point F, which partitions the directed line segment from d to E into a 5:6 ratio is $\frac{15}{2}$ . Thus the answer is Fifteen-halves.

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2 years ago

X²+Y²=250 and XY=117 What are the values of X and Y?

yan [13]

Answer:

Step-by-step explanation:

$x^2+y^2=250\\\\x^2-2xy+y^2+2xy=250\\\\(x-y)^2=250-2xy\\\\(x-y)^2=250-2\cdot117\\\\ (x-y)^2=16\\\\x-y=4\qquad\qquad\vee\qquad \qquad x-y=-4\\\\x=4+y \qquad\qquad \vee\qquad\qquad x=-4+y\\\\(y+4)y=117\qquad\vee\qquad\quad (y-4)y=117\\\\y^2+4y-117=0\qquad\vee\qquad y^2-4y-117=0\\\\y=\dfrac{-4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\qquad\vee\qquad y=\dfrac{4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\\\\y=\dfrac{-4\pm\sqrt{16+468}}{2}\qquad\ \ \vee\qquad y=\dfrac{4\pm\sqrt{16+468}}{2}$

$y_1=\dfrac{-4-22}{2}\ ,\quad y_2=\dfrac{-4+22}{2}\ ,\quad y_3=\dfrac{4-22}{2}\ ,\quad y_4=\dfrac{4+22}{2}\\\\y_1=-13\ ,\qquad y_2=9\ ,\qquad\quad\qquad\ y_3=-9\ ,\qquad y_4=13\\\\x_{1,2}=4+y_{1,2}\qquad\qquad\qquad\qquad\qquad x_{3,4}=-4+y_{3,4}\\\\x_1=-9\ ,\qquad x_2=13\ ,\qquad\quad\qquad x_3=-13\ ,\qquad x_4=9$