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zmey [24]
3 years ago
5

Please math , help

Mathematics
1 answer:
Furkat [3]3 years ago
7 0

Answer:

As both the mean and standard deviation are in the desired ranges, the tool passes the technical control.

Step-by-step explanation:

Mean of the batch:

The mean of the batch is the sum of all values divided by the number of items. So

M = \frac{199+204+201+197+195+204+200}{7} = 200

Mean in the desired interval.

Standard deviation:

Square root of the sum of the difference squared between each term and the mean, divided by the number of items. So

S = \sqrt{\frac{(199-200)^2+(204-200)^2+(201-200)^2+(197-200)^2+(195-200)^2+(204-200)^2+(200-200)^2}{7}} = 1.18

As both the mean and standard deviation are in the desired ranges, the tool passes the technical control.

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What is the kinetic Energy of a 110 kg linebacker rushing towards his football
Leviafan [203]

<u>Answer:</u>

The Kinetic energy of the 110 kg linebacker is 1375 J

<u>Solution:</u>

The kinetic energy of an object is the energy produced by its velocity. Kinetic energy of an object is directly proportional to the mass and the square of the its velocity.

Therefore, the formula for kinetic energy is

KE=\frac{1}{2} \times m v^{2}

Here, The linebacker’s mass m = 110 kg

The linebacker’s velocity v = 5 m/s

So by substituting the values,

The kinetic energy of linebacker is

K E=\left(\frac{1}{2} \times 110 \times 5 \times 5\right) \text { Joules } \\\\ \Rightarrow (\frac{2750}{2}) Joules = 1375 Joules

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Step-by-step explanation:

The formatting is likely incorrect for these two options:

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