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zmey [24]
2 years ago
5

Please math , help

Mathematics
1 answer:
Furkat [3]2 years ago
7 0

Answer:

As both the mean and standard deviation are in the desired ranges, the tool passes the technical control.

Step-by-step explanation:

Mean of the batch:

The mean of the batch is the sum of all values divided by the number of items. So

M = \frac{199+204+201+197+195+204+200}{7} = 200

Mean in the desired interval.

Standard deviation:

Square root of the sum of the difference squared between each term and the mean, divided by the number of items. So

S = \sqrt{\frac{(199-200)^2+(204-200)^2+(201-200)^2+(197-200)^2+(195-200)^2+(204-200)^2+(200-200)^2}{7}} = 1.18

As both the mean and standard deviation are in the desired ranges, the tool passes the technical control.

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