The answer to your question is $720
Answer:
∴Given Δ ABC is not a right-angle triangle
a= AB = √45 = 3√5
b = BC = 12
c = AC = √45 = 3√5
Step-by-step explanation:
Given vertices are A(3,3) and B(6,9)
![AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7Bx_%7B2%7D-x_%7B1%7D%20%29%5E%7B2%7D%20%2B%28y_%7B2%7D-y_%7B1%7D%20%29%5E%7B2%7D%20%20%7D)
AB = ![\sqrt{(9-3)^{2}+(6-3)^{2} } = \sqrt{6^{2}+3^{2} } =\sqrt{45}](https://tex.z-dn.net/?f=%5Csqrt%7B%289-3%29%5E%7B2%7D%2B%286-3%29%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B6%5E%7B2%7D%2B3%5E%7B2%7D%20%20%7D%20%3D%5Csqrt%7B45%7D)
Given vertices are B(6,9) and C( 6,-3)
= ![\sqrt{(-3-9)^{2}+(6-6)^{2} } =\sqrt{12^{2} } = 12](https://tex.z-dn.net/?f=%5Csqrt%7B%28-3-9%29%5E%7B2%7D%2B%286-6%29%5E%7B2%7D%20%20%7D%20%3D%5Csqrt%7B12%5E%7B2%7D%20%7D%20%3D%2012)
BC = 12
Given vertices are A(3,3) and C( 6,-3)
![AC = \sqrt{(6-3)^{2}+(-3-3)^{2} } = \sqrt{9+36} = \sqrt{45}](https://tex.z-dn.net/?f=AC%20%3D%20%5Csqrt%7B%286-3%29%5E%7B2%7D%2B%28-3-3%29%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B9%2B36%7D%20%3D%20%5Csqrt%7B45%7D)
AC² = AB²+BC²
45 = 45+144
45 ≠ 189
∴Given Δ ABC is not a right angle triangle
Answer:
93,000 mL
Step-by-step explanation:
1 l = 1000 mL
93 L * (1000 mL)/(1 L) = 93,000 mL