Answer:
Arithmetic sequence
f(n) = 5n + 2
Step-by-step explanation:
f(1) = 7
f(2) = 7 + 5
f(3) = 7 + 5 + 5 = 7 + (2)(5)
f(n) = 7 + (n-1)(5)
f(n) = 7 + 5n - 5
f(n) = 5n + 2
Answer:
x^(5/6) + 4(x^(7/3))
Step-by-step explanation:
Simplify x to the 1/3 power MULTIPLIED BY (x to the 1/2 power + 2x to the 2 power )
Simplify x^(1/3) × (x^(1/2) + (2x)^2)
= x^(1/3)(x^(1/2)) + x^(1/3)((2x)^2)
= x^(1/3+1/2) + 4(x^(1/3+2))
= x^(5/6) + 4(x^(7/3))
x^(1/3) is y such that y^3 = x
(x^(1/3) × x^(1/3) × x^(1/3)) = x^(1/3+1/3+1/3) = x^1 = x
x^(1/2) = √2 = y such that y^2 = x
(2x)^2 = 4x^2
Sin51=y/12
y=12sin51 units
y≈9.33 units (to nearest hundredth of a unit)
...
tanα=12/5
α=arctan2.4°
α≈67.38° (to nearest hundredth of a degree)
...
tan13=x/24
x=24tan13 units
x≈5.54 units (to nearest hundredth of a unit)
...
sin20=10/x
x=10/sin20 units
x≈29.24 units (to nearest hundredth of a unit)
Answer:
The school is closest
Step-by-step explanation:
Plot the point of the library and measure the distance from the library to each location.
Since the diameter is 6 cm, the radius is 3 cm. Use the area formula to get 113.04 cm squared. Then, you multiply that by the height of the rod, which is 20 cm. The volume of one rod is 2260.8 cm cubed. To find how much steel is needed for 189 rods, multiple the volume of one rod by 189. Your answer should be 427291.2 cm³.