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3 years ago

Anyone please help mee with geometry

Mathematics

1 answer:

Nookie1986 [14]3 years ago

8 0

Answer:

y = 5

Step-by-step explanation:

Because of the perpendicular bisector, we know that WZ is congruent to WX. Therfore, we can set their equations as equal to eachother and solve for y.

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jennifer walks 8 miles in the same time she can jog 13 miles. if her jogging speed is 8mph faster than her walking speed, how fa

Elanso [62]

Answer:

12.8mph

Step-by-step explanation:

Let 'w' represent her walking speed

->if her jogging speed is 8mph faster than her walking speed

Jogging speed= w+8

Using the time equation i.e time = dist/speed

For walking when distance is 8miles

time = dist / speed= 8/w hrs

For jogging when distance is 13miles

time = dist / speed= 13/(w+8) hrs

Equating the time

jog time = walk time

13/(w+8) = 8/w

By cross multiplying it

13w = 8w + 64

5w = 64

w=64/5

w=12.8mph

Therefore, 12.8mph is her walking speed.

5 0

3 years ago

Solve the Inequality for x<br><br><br> –8x + 16 > –72

erastova [34]

Answer:

Inequality Form:

x< 11

Interval Notation:

( − ∞ , 11 )

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

4 0

3 years ago

A circular garden has a circumference of

omeli [17]

This solution to this problem is predicated on the fact that the circumference is just: $2\pir$ . A straight line going through the center of the garden would actually be the diameter, which is well known to be two times the radius of the circle, so we can say that the circumference is just:

$d\pi$

So, solving for both the radius and the diameter gives us:

$d\pi=8xy^2\pi\\ d=8xy^2\\ \\ 2\pi r=8xy^2\pi\\ r=4xy^2$

So, the length of thes traight path that goes through the center of the guardain is just $8xy^2$ , and we can use the radius for the next part of the problem.