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Alex Ar [27]
3 years ago
5

Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D is the trian

gular region enclosed by the lines y = 0, y = 2x, and x + 2y = 1; rho(x, y) = x

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
4 0

Answer:

m=1/300 du

Step-by-step explanation:

we have that m=∫∫rho(x,y)dA for this we must find the limits of integration (according to the graph1)

On the x axis: if y=2x and x+2y=1 then y=2x and y=(1-x)/2 ⇒ 2x=(1-x)/2 ⇒ 4x=1-x ⇒ 5x=1 ⇒ x=1/5; on the y axis y=0 and y=1/2

m=∫∫rho(x,y)dA (view the graph 2)

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I need help what is n?
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Answer:

x=-7

Step-by-step explanation:

-30=5(x+1)

6-1(x+1)

x=-1-6

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The mean percentage of a population of people eating out at least once a week is 57% with a standard deviation of 3.50%. Assume
Fed [463]
Since 68% of the sample ranges from the plus minus first standard deviation from the mean, then interval wherein it will occur will be between 53.5% to 60.5%. I got this answer through adding and subtracting one standard deviation (3.5) from the mean (which is 57). 
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Math help please (80 points)
Inga [223]

Answer:

1. x^4 -x^3 -4x^2 -3

a1 = -7.4

an = an-1 -13.8  (choice 1)

Step-by-step explanation:

f(x) = x^4 -x^2 +9

g(x) = x^3 +3x^2 +12

We are subtracting

f(x) -g(x) =x^4 -x^2 +9 - ( x^3 +3x^2 +12)

Distribute the minus sign

x^4 -x^2 +9 -  x^3 -3x^2 -12

I like to line them up vertically

x^4      -x^2 +9

-  x^3 -3x^2 -12

-------------------------

x^4 -x^3 -4x^2 -3


2.  a1 = -7.4

To find the common difference, take term 2 and subtract term 1

-21.2 - (-7.4)

-21.2 + 7.4

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The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.​
melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

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The nth term of an AP is:

\mathbf{T_n = a + (n - 1)d}

So, the <em>2nd, 6th and 8th terms </em>of the AP are:

\mathbf{T_2 = a + d}

\mathbf{T_6 = a + 5d}

\mathbf{T_8 = a + 7d}

The <em>first, second and third terms </em>of the GP would be:

\mathbf{a_1 = a + d}

\mathbf{a_2 = a + 5d}

\mathbf{a_3 = a + 7d}

The common ratio (r) is calculated as:

\mathbf{r = \frac{a_2}{a_1}}

This gives

\mathbf{r = \frac{a + 5d}{a + d}}

The nth term of a GP is calculated using:

\mathbf{a_n = a_1r^{n-1}}

So, we have:

\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

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