The difference between the sum of all eight positive integral divisors of 66 and the sum of all eight positive integral divisors of 70 is zero.
<h3>How to find the difference between the integral divisors?</h3>
First let's find the integral divisors. We can write 66 as a product of prime numbers as:
66 = 33*2 = 2*3*11
Then the integral divisors of 66 are:
2
3
11
2*3 = 6
2*11 = 22
3*11 = 33
1 (trivially)
66 (trivially)
The sum gives:
2 + 3 + 11 + 6 + 22 +33 + 1 + 66 = 144
For 70 we have:
70 = 7*10 = 2*5*7
Then the integral divisors are:
1
70
2
5
7
2*5 = 10
2*7 = 14
5*7 = 35
The sum gives:
1 + 70 + 2 +5 + 7 + 10 + 14 + 35 = 144
Then the difference between these two sums is:
144 - 144 = 0
If you want to learn more about integral divisors:
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Answer:
$31728
Step-by-step explanation:
sorry if I'm wrong
Answer:
x=2
Step-by-step explanation:
2.1(2.3 + 2.1x) = 11.65 + x
Distribute
4.83+4.41x=11.65+x
bring 4.83 over (-)
4.41x=6.82+x
bring x over
4.41x-1(x)=6.82
4.41-1=3.41 so
3.41x=6.82
divide 3.41
x=2
Answer:
$68.8
Step-by-step explanation:
27.52/2 = 13.76
13.76 x 5 = 68.8
36.25/5 = 7.25
The first digit of the quotient is in the ones. Paul is correct.
