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bekas [8.4K]
2 years ago
10

Quadrilateral ABCD undergoes a reflection across the x-axis to form quadrilateral A'B'C'D'. The coordinates of A' are ( , ).

Mathematics
2 answers:
natka813 [3]2 years ago
5 0
1) A(-5,-3); B(-6,-1); C(-3,-1) ; D(-2,-3)

When a refection is done about x-axis, the values of the abscise x remain identical & the value of ordinate  just change their signs:
A(-5,-3); A'(-5,+3)
B(-6,-1); B'(-6,+1)
C(-3,-1); C'(-3,+1)
D(-2,-3); D'(-2,+3)

2) A'B'C'D' is translated 3 UNITS RIGHT, that means the ordinated of A'B'C'D'
are the same but the abscises have been increased by 3 UNITS ;

A'(-5,+3) ==>A"(-2,3)
B'(-6,+1) ==>B"(-3,1)
C'(-3,+1) ==>C"(0,1)
D'(-2,+3) ==>D"(1,3)
ioda2 years ago
4 0

Answer:

im confused ash

Step-by-step explanation:

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Answer:

x = -2

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Step-by-step explanation:

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3 years ago
Find the constant of variation k for the direct variation. x f ( x ) 0 0 2 –1 4 –2 7 –3.5 k = 0.5 k = –2 k = –0.5 k = 0
Furkat [3]

Answer:

Option C is correct.

Constant of variation k = -0.5

Step-by-step explanation:

The direct variation says that:

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Given the table:

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