Quadrilateral ABCD undergoes a reflection across the x-axis to form quadrilateral A'B'C'D'. The coordinates of A' are ( , ).

Mathematics

2 answers:

natka813 [3]3 years ago

5 0

1) A(-5,-3); B(-6,-1); C(-3,-1) ; D(-2,-3)

When a refection is done about x-axis, the values of the abscise x remain identical & the value of ordinate just change their signs:
A(-5,-3); A'(-5,+3)
B(-6,-1); B'(-6,+1)
C(-3,-1); C'(-3,+1)
D(-2,-3); D'(-2,+3)

2) A'B'C'D' is translated 3 UNITS RIGHT, that means the ordinated of A'B'C'D'
are the same but the abscises have been increased by 3 UNITS ;

A'(-5,+3) ==>A"(-2,3)
B'(-6,+1) ==>B"(-3,1)
C'(-3,+1) ==>C"(0,1)
D'(-2,+3) ==>D"(1,3)

ioda3 years ago

4 0

Answer:

im confused ash

Step-by-step explanation:

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qaws [65]

ANSWER=5.2

EXPLANATION

This triangle shows a example of the Pythagorean Theorem, which means the equation is gonna be

a^2+b^2=c^2

The variables a and b are the straight sides of the triangle, while the variable c  is the curved side on the triangle, or what we are trying to find in this question.

Firstly let’s take the two sides that already have a number shown, also known in the Pythagorean Theorem as sides a and b.

2^2+4.8^2=c^2

Now we want to square the two given numbers to get the equation

4+23.04=c^2

Now we add the two given numbers that we have now squared to get the equation

27.04=c^2

The final step will now be to take the number (27.04) and square root it, which should give you the answer, 5.2

6 0

3 years ago

Find the angle between u= V51 - 8; and v= 151+x. Round to the nearest tenth of a degree.

Igoryamba

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