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3 years ago

Anyone in 10th grade geometry I could really use a partner to help me with it please?! :)

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

4 0

Answer:

I can help

Step-by-step explanation:

I'm in honors classes

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Evaluate <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%5E%7B-2%7Dx%5E%7B-3%7Dy%5E%7B5%7D%20%7D" id="TexFormula1" title="\

Irina18 [472]

Answer:

$\bf C)\: -\cfrac{1}{32}$

Step-by-step explanation:

$\tt \cfrac{1}{2^{-2}x^{-3}y^5}$

$\tt x=2\\y=-4$

Substitute ''x'' with '2' & 'y' with "-4":-

$\tt \cfrac{1}{2^{-2}\times \:2^{-3}\left(-4\right)^5}$

First let's solve $\tt 2^{-2}\times \:\:2^{-3}\left(-4\right)^5$

$\tt 2^{-2}\times \:2^{-3}=\boxed{\cfrac{1}{32} }$

$\tt \cfrac{1}{32}\left(-4\right)^5$

Calculate exponents:- -4^5= -1024

$\tt \cfrac{1}{32}\left(-1024\right)$

Remove parentheses, apply rule:- $\tt a\left(-b\right)=-ab$

$\tt-\frac{1}{32}\times \:1024$

$\tt \cfrac{1}{32}\times \cfrac{1024}{1}$

Apply fraction rule:-

$\tt -\cfrac{1\times \:1024}{32\times \:1}$

$\tt \cfrac{1024}{32}$

Divide numbers:-

$\tt -32$

Now that we're done factoring the denominator let's bring down the numerator which is ' 1 ':-

$\tt -\cfrac{1}{32}\;\; \bf Answer$

☆-------☆-------☆-------☆

3 0

2 years ago

Read 2 more answers

The sum of three numbers is 110. The third number is 3 times the first. The second number is 5 more than the first. What are the

g100num [7]

Answer:

The numbers are 63, 26, & 21

Step-by-step explanation:

110 = 3x + (5 + x) + x

105 = 3x + 2x

105 = 5x

21 = x

Plug it back into the first equation to find your values

6 0

3 years ago

Evaluate the expression when x=3 and y=-4 . -6x+y Easyyyy....

RSB [31]

Answer:

-22

Step-by-step explanation:

7 0

3 years ago

HELP ASAP: https://auro.reeee.ee/uD3ocP

Simora [160]

I swear i just saw this on discord

8 0

2 years ago

Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence i

Pavlova-9 [17]

Answer:

$\bar X = \frac{Lower +Upper}{2}$

$\bar X= \frac{1.9+3.3}{2}= 2.6$

And the margin of error with this one:

$\bar X = \frac{Upper-Lower}{2}$

$ME = \frac{3.3-1.9}{2}= 0.7$

Step-by-step explanation:

Assuming that the parameter of interest is the sample mean $\mu$ . And we can estimate this parameter with a confidence interval given by this formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

For this case the confidence interval is given by (1.9, 3.3)

Since the confidence interval is symmetrical we can estimate the sample mean with this formula:

$\bar X = \frac{Lower +Upper}{2}$

$\bar X= \frac{1.9+3.3}{2}= 2.6$

And the margin of error with this one:

$\bar X = \frac{Upper-Lower}{2}$

$ME = \frac{3.3-1.9}{2}= 0.7$

7 0

3 years ago