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Vesnalui [34]
3 years ago
11

Confused on this one. I need someone to help me out.

Mathematics
1 answer:
Arlecino [84]3 years ago
6 0
The answer is T=PV/nR

Hope this helps!
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Find the slope of the line that passes through ( 2 , 7 ) and ( – 4 , 19 ) .
12345 [234]

Answer:

-2

Step-by-step explanation:

slope form: y2-y1/x2-x1

points: x1, y1 (2,7)  and x2,y2 (-4,19)

substitute the points into the form: 19-7/-4-2

simplify: 12/-6 = -2

8 0
1 year ago
Draw a line representing the "run" and a line representing the "rise" of the line. State the slope of the line in simplest form.
Igoryamba

Answer:

The answer is "\bold{\frac{9}{13}}"

Step-by-step explanation:

In this question, the image file is missing, which is defined in the attached file. please find it.

\to raise= y_2-y_1

             =-1-(-10)\\\\=-1+10\\\\=9

\to run= x_2-x_1

          =9-(-4)\\\\=9+4\\\\=13

\to \text{formula for slope} =\frac{rise}{run} =\frac{9}{13}

7 0
3 years ago
5-7+6+(-3)-1-(-8) simplify
Airida [17]
Your answer would be <span><span><span><span>5−7</span>+6</span>−3</span>−1</span>−<span>(<span>−8</span>) = 8</span>
6 0
4 years ago
18. A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be
avanturin [10]

Answer:

a. =50 ± 4.67

b. =50 ± 4.81  

decreasing the sample size increase the margin of error

c. =50 ± 3.51

decreasing the confidence level reduced the margin of error

d. No.  because the confidence interval coefficient is gotten from the table of normal distribution of Z value.  therefore the confidence interval is only used for normal distributed population

Step-by-step explanation:

given

The sample mean, x, = 50,

the sample standard deviation, s, = 8.

a. Construct a 98% confidence interval for m if the sample size, n, is 20

for a 98% confidence interval of an infinite population, thus for a sample of size N and mean x, drawn from an infinite population having a standard deviation of σ, the mean value of the population is estimated to by:

x± 2.33σ /√N

for a confidence level of 98%, Zc = 2.33 gotten from the table of confidence interval.

This indicates that the mean value of the population lies between

50- ( 2.33*8 /√20)      and 50+ ( 2.33*8 /√20)

with 98% confidence in this prediction.

=50 ± 4.67

=45.33 or 54.67

(b) Construct a 98% confidence interval for m if the sample size, n, is 15.

using the same method as above

x± 2.33σ /√N

This indicates that the mean value of the population lies between

50- ( 2.33*8 /√15)      and 50+ ( 2.33*8 /√15)

=50 ± 4.81

=45.19 or 54.81

decreasing the sample size increase the margin of error

(c) Construct a 95% confidence interval for m if the sample size, n, is 20. Compare the results to those obtained in part

95% confidence interval =1.96 (gotten from table of confidence coefficient)

using x±1.96 σ /√N

This indicates that the mean value of the population lies between

50- (1.96 *8 /√20)      and 50+ (1.96 *8 /√20)

=50 ± 3.51

=46.49 or 53.51

c. decreasing the confidence level reduced the margin of error

(d) Could we have computed the confidence intervals in parts (a)–(c) if the population had not been normally distributed?

No.  because the confidence interval coefficient is gotten from the table of normal distribution of Z value.  therefore the confidence interval is only used for normal distributed population

7 0
3 years ago
Solve: 6x + 10 = 4x -8. Determine how many solutions? (exactly one, infinitely many, no solution)
Vesnalui [34]
  • Answer:

<em>x = - 9</em>

  • Step-by-step explanation:

<em>6x + 10 = 4x - 8</em>

<em>6x - 4x = - 10 - 8</em>

<em>2x = - 18</em>

<em>x = - 18 : 2</em>

<em>x = - 9</em>

7 0
3 years ago
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