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3 years ago

Please Solve this. Last Question of the Day So Points Increase a little bit. :)

Mathematics

2 answers:

zlopas [31]3 years ago

6 0

found this, hope it helps

ICE Princess25 [194]3 years ago

6 0

Answer:

5 cookies left

Step-by-step explanation:

First you make the fraction equal by multiplying them

2/3 multiply both numerator and denominator by 4

= 8/12

Now you divide 60 by 12 to find the amount to make the denominator 60

60 divided by 12 = 5

8/12 multiply both numerator and denominator by 5

= 40/60

So now we know the amounts

She gave 40 away so she has 20 left (60 - 40 = 20)

Now make 3/4 numerator and denominator by equal to 20

Multiply them by 5

15/20

She had 5 cookies left

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I need to know how to write an equation whose solution is x=3.5 but i don't know how

inysia [295]

Answer:

2x+5=12

Step by-step explanation:

2x+5=12

Subtract 5

2x=7

Divide each side by 2

x=3.5

7 0

4 years ago

Rewrite the function by completing the square. f(x)= 2x^{2}+3x-2f(x)=2x 2 +3x−2

Elena L [17]

Answer:

$2\Bigl[(x+\frac{3}{4} )^2-\frac{25}{16} \Bigr]$

Step-by-step explanation:

Step 1

We factor out 2 so that the coefficient of the quadratic term is 1.

$f(x)=2x^2+3x-2\\f(x)=2\bigl(x^2+\frac{3}{2} -1\bigr)$

Step 2

In this step we add and subtract the square of the coefficient of the x term, this term is $\Bigl(\frac{1}{2} \bigl(\frac{3}{2}\bigr)\Bigr)^2$ . This is the step where we complete the square.

$f(x)=2\Bigl[x^2+\frac{3}{2}x+(\frac{3}{4})^2-(\tfrac{3}{4})^2 -1 \Bigr]\\f(x)=2\Bigl[x^2+\frac{3}{2}x+(\frac{3}{4})^2-\frac{25}{16} \Bigr]$

Step 3

In this step we factor out the perfect square tri-nomial formed by the first 3 terms in last line of step 2. This calculation is shown below,

$f(x)=2\Bigl[\bigl(x+\frac{3}{4} \bigr)^2-\frac{25}{16} \Bigr]$

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3 years ago

What's the ratio 20:44

Lelechka [254]

This becomes 10:22, then 5:11.

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Stells [14]

Answer:

Step-by-step explanation:

subtracted it because it says drop.

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4 years ago