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Oliga [24]
3 years ago
7

(2^3)^2 (2^-2) / (2^2) (2^0)

Mathematics
2 answers:
fgiga [73]3 years ago
6 0

Answer:  4

Step-by-step explanation:

The answer is 4

Dmitry [639]3 years ago
3 0

Answer:

(2^3)^2 (2^-2) / (2^2) (2^0)

{2}^{3}  \times  {2}^{3}  \times 0 \div  {2}^{2}  \times 1 = 0

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The maximum value of the function: f(x)= -5 x ^2 +30x-200 is?
VARVARA [1.3K]

Answer:

\displaystyle    - 155

Step-by-step explanation:

we are given a quadratic function

\displaystyle f(x) =  - 5 {x}^{2}  + 30x - 200

we want to figure out the minimum value of the function

to do so we need to figure out the minimum value of x in the case we can consider the following formula:

\displaystyle x _{ \rm  min} =  \frac{ - b}{2a}

the given function is in the standard form i.e

\displaystyle f(x) = a {x}^{2}  + bx + c

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thus substitute:

\displaystyle x _{ \rm  min} =  \frac{ - 30}{2. - 5}

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\displaystyle x _{ \rm  min} =  \frac{ - 30}{ - 10}

simply division:

\displaystyle x _{ \rm  min} =  3

plug in the value of minimum x to the given function:

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simplify multiplication:

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simplify:

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