Answer:
for this type of question, integral by parts should be used . This involves using the formula for intregation by parts:
intudv=uv-intvdu.
lets first break apart the x and e10x into two parts - "u" and "v"
where u = x.
however, we need to find the value of v. in order to do this, we can integrate dv/dx in order to get to v.
the value of dv/dx is : e10x
u = x dv/dx = e10x
as seen in the formula, you need to have a value for u, dv, v and du.
therefore in order to get du you must differentiate u:
u = x
du/dx = 1
du = 1dx = dx
du = dx
in order to get v you need to integrate dv/dx:
\displaystyle \inte10x dx = 1/10 x10x
now that we have both parts, we can put this back into the formula.
intudv=uv-intvdu.
\displaystyle \intxe10x = x * 1/10e10x - \displaystyle \int1/10e10x dx
Step-by-step explanation:
Why now :cccccccccccccccccc
Answer: The correct option is (B) 24 : 25.
Step-by-step explanation: Given that the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2 : 3.
We are to find the ratio of the area of R to the area of S.
Let 2x, 3x be the sides of rectangle R and y be the side of square S.
Then, according to the given information, we have

Therefore, the ratio of the area of R to the area of S is
![\dfrac{2x\times3x}{y\times y}\\\\\\=\dfrac{5x^2}{y^2}\\\\\\=6\left(\dfrac{x}{y}\right)^2\\\\\\=6\times\left(\dfrac{2}{5}\right)^2~~~~~~~~~~~[\textup{Using equation (i)}]\\\\\\=\dfrac{24}{25}\\\\=24:25.](https://tex.z-dn.net/?f=%5Cdfrac%7B2x%5Ctimes3x%7D%7By%5Ctimes%20y%7D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B5x%5E2%7D%7By%5E2%7D%5C%5C%5C%5C%5C%5C%3D6%5Cleft%28%5Cdfrac%7Bx%7D%7By%7D%5Cright%29%5E2%5C%5C%5C%5C%5C%5C%3D6%5Ctimes%5Cleft%28%5Cdfrac%7B2%7D%7B5%7D%5Cright%29%5E2~~~~~~~~~~~%5B%5Ctextup%7BUsing%20equation%20%28i%29%7D%5D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B24%7D%7B25%7D%5C%5C%5C%5C%3D24%3A25.)
Thus, the required ratio of the area of R to the area of S is 24 : 25.
Option (B) is CORRECT.
No, she is wrong. 0.00001 has 4 zeros in front of the one and behind the decimal, making it 1/100000 or 1/10^5. For 0.001, there are 2 zeros in front, making it 1/1000 or 1/10^3. Since a number gets smaller as the denominator gets larger, and 10^5>10^3, 1/10^5<1/10^3