Answer:
ASA
Step-by-step explanation:
∠BAC ≈ ∠CAD
AC = AC
∠BCA ≈ ∠ACD
The amount that the bank loaned out at 7.9% is $1,574.00
How do represent the amounts lent at different rates?
On the assumption that x amount was loaned at 7.9% and that the remaining amount, (8,200-x) was loan out at 7.4%, we can determine the interest charged on each loan as the loan multiplied by the interest rate
interest on 7.9% loan=7.9%*x=0.079x
interest on 7.4% loan=7.4%*(8200-x)
interest on 7.4% loan=606.80-0.074x
total interest=0.079x+606.80-0.074x
total interest=0.005x+606.80
total interest on loans=614.67
614.67=0.005x+606.80
614.67-606.80=0.005x
7.87=0.005x
x=7.87/0.005
x=amount loaned at 7.9%=$1,574.00
y=$8200-$1574
y=$6,626.00
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Answer:
Step-by-step explanation:
f(x) = 1/4 x²+bx+10
the derivate is : f'(x) = 1/2 x +b
you have : f'(6)=0
1/2 (6)+b=0
3+b =0
b = -3
so f(x) = 1/4 x²-3x+10.......f(6) =1/4(6)² -3(6)+10 =9-18+10 =1
f(x) = 1/4(x-6)²+1... the vertex form
