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anygoal [31]
3 years ago
14

Suppose that you are given a decision situation with three possible states of nature: S1, S2, and S3. The prior probabilities ar

e P(S1) = 0.16, P(S2) = 0.57, and P(S3) = 0.27. With sample information I, P(I | S1) = 0.13, P(I | S2) = 0.07, and P(I | S3) = 0.19. Compute the revised or posterior probabilities: P(S1 | I), P(S2 | I), and P(S3 | I). If required, round your answers to four decimal places.
Mathematics
1 answer:
seropon [69]3 years ago
6 0
The answer would be 1.0067
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An apple orchard sold 155 apples in September in November it sold 17 times as many apples as it did in September how many apples
borishaifa [10]

9514 1404 393

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8 0
3 years ago
I need help 9-16!!Thank u!
Trava [24]

Answer:9-16=-7


Step-by-step explanation:


5 0
3 years ago
Help I’ll do anything just help
Gnom [1K]

Answer:

1) {n}^{2}  - 81 \\ (n - 9)(n + 9)

2) \:  \: {a}^{2}  - 121 \\ (a - 11)(a + 11)

3) \:  \:  {n}^{2}  - 16 \\ (n - 4)(n + 4)

4)  \:  \: 9 {x}^{2}  - 144 \\  {3}^{2}  {x}^{2}  -  {12}^{2}  \\ (3x - 12)(3x + 12)

5) \: 2 {x}^{2}  - 9 \\ (2x - 3)(x + 3)

6) \:  \: 4 {w}^{2}  - 9 \\  {2}^{2}  {w}^{2}  -  {3}^{2}  \\ (2w + 3)(2w - 3)

7) \:  \: 4 {n}^{2}  - 1 \\  {2}^{2}  {n}^{2}  -  {1}^{2}  \\ (2n  + 1)(2n - 1)

8) \:  \: 1 - 16 {x}^{2}  \\  {1}^{2}  -  {4}^{2}  {x}^{2}  \\ (1 - 4x)(1  +  4x)

9) \:  \: {x}^{2}   - {y}^{2}  \\ (x - y)(x + y)

10) \:  \: 9 -  {c}^{2}  \\  {3}^{2}  -  {c}^{2}  \\ (3 - c)(3 + c)

11) \:  \:  {n}^{2} -  25 \\  {n}^{2}  -  {5}^{2}  \\ (n + 5)(n - 5)

13)49 - 4 {a}^{2}  \\  {7}^{2}  -  {2}^{2}  {a}^{2}  \\ (7 - 2a)(7 + 2a)

14) {a}^{2}  {b}^{2}  -  {c}^{4}  \\ (ab -  {c}^{2} )(ab +  {c}^{2} )

15) \:  \: 4  {x}^{2}  {y}^{2}  - 9 {z}^{2} \\  {2}^{2}   {x}^{2}  {y}^{2}  -  {3}^{2}  {z}^{2}  \\ (2xy - 3z)(2xy + 3z)

hope this helps

sorry, I don't know how solve the 12th one.

thanks.

7 0
3 years ago
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