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anygoal [31]
3 years ago
14

Suppose that you are given a decision situation with three possible states of nature: S1, S2, and S3. The prior probabilities ar

e P(S1) = 0.16, P(S2) = 0.57, and P(S3) = 0.27. With sample information I, P(I | S1) = 0.13, P(I | S2) = 0.07, and P(I | S3) = 0.19. Compute the revised or posterior probabilities: P(S1 | I), P(S2 | I), and P(S3 | I). If required, round your answers to four decimal places.
Mathematics
1 answer:
seropon [69]3 years ago
6 0
The answer would be 1.0067
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X = large boxes and y = small boxes

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60(70 - y) + 65y = 4300
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6 0
3 years ago
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