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Leona [35]
4 years ago
15

How to solve -6r(4r-5)-2(r-2) plz...

Mathematics
1 answer:
wlad13 [49]4 years ago
6 0

-6r(4r - 5) - 2(r - 2)

(-6r).4r - 5.(-6r) - 2.r - 2.(-2)

-24r² + 30r - 2r + 4

-24r² + 28r + 4

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A cylinder has a height of 13 feet and a radius of 11 feet. What is its volume? Use a ~ 3.14
ArbitrLikvidat [17]

Answer:

900

Step-by-step explanation:

V=πr2h

3.14 x 11= 34.54

34.54 x 2= 69.08

69.08x 13= 898.04

898.04 rounded to nearest hundreth is 900

8 0
3 years ago
Jim earns 1,600 per month after taxes. he is working on his budget and has the first threecategories finished. Housing $576 Food
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4 0
3 years ago
K^2+8k-9=0 can you help me solve with showing work
givi [52]
Using the PSN method:

P = -9
S = 8
So N = 9,-1

Using 9 and -1 in the original equation gives:

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\\(k-1)(k+9)

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7 0
3 years ago
Read 2 more answers
If there are x teams in a sports​ league, and all the teams play each other​ twice, a total of​ n(x) games are​ played, where ​n
EleoNora [17]
1.
Consider a group of n objects. Assume we want to form groups of r, from these n objects.

There are in total C(n, r)= \frac{n!}{r!(n-r)!} many ways of doing so.

where, r! is "r factorial", calculated as 1*2*3*...*(r-1)*r

2.

C(x, 2) is the total number of pairs out of x objects, that we can form.

so let the x objects represent the x teams, and 2, represent a group of 2, which means a game.

The total number of games is:

n(x)=2*C(x, 2) = 2*  \frac{x!}{2!(x-2)!}= \frac{x!}{(x-2)!}= \frac{x(x-1)(x-2)!}{(x-2)!}=x(x-1)= x^{2} -x

Remark, we multiplied by 2, since there will be 2 matches for each pair of teams.


Answer: x^{2} -x

6 0
3 years ago
It's cool sold 1020 tickets for a benefit concert. For ticket sales were 85% of the seating capacity of the school auditorium. H
fgiga [73]
There would be 1,200 seats in the auditorium. 
8 0
3 years ago
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