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2 years ago

PLS HELP AGAIN ASAP THIS THE SECOND TO LAST PROBLEM ON MORE AFTER THIS

Mathematics

1 answer:

Rufina [12.5K]2 years ago

3 0

Answer:

140

Step-by-step explanation:

because 2 cups of flour turned to 20 cups is to 14 cups of sugar to 140 cups

so the ratio goes from 2: 14 to 20: 140

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The graph of a linear function is given below. What is the zero of the function ?

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A, 2 is the y intercept not the zero

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64 times -7/8 minus 1/2

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$64 \times (- \dfrac{7}{8}) - \dfrac{1}{2}$

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2 years ago

What is -7 plus 7 equal too

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Step-by-step explanation:

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A conical vessels with base radius 5 cm and height 24cm is full of water this water is emptied into a cylindrical vessel of base

Aliun [14]

Answer:

$2\ cm$

Step-by-step explanation:

$We\ are\ given\ that,\\Radius\ of\ the\ conical\ vessel=5\ cm\\Height\ of\ the\ conical\ vessel=24\ cm\\Hence,\\As\ we\ know\ that,\\Volume\ of\ a\ cone=\frac{1}{3}\pi r^2h\\Hence,\\The\ volume\ of\ the\ conical\ vessel=\frac{1}{3}\pi (5)^224= \frac{1}{3}\pi 25*24=200\pi \\Hence,\\The\ volume\ of\ the\ conical\ vessel=The\ amount\ of\ water\ filled\ in\ it\\Hence,\\The\ amount\ of\ water\ filled\ in\ the\ conical\ vessel=200\pi\\Lets\ consider\ the\ cylindrical\ vessel:\\Volume\ of\ a\ cylinder=\pi r^2h$

$As\ we\ are\ not\ said\ that\ the\ cylindrical\ vessel\ was\ empty,\ let\ its\ initial\\ height\ be\ h_1\\Radius\ of\ the\ Cylindrical\ vessel=10\ cm\\Initial\ height\ of\ the\ cylindrical\ vessel=h_1\\Initial\ volume\ of\ the\ cylindrical\ vessel=\pi *10^2*h_1=100h_1\pi \\Initial\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi \\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=Final\ amount\ of\ water\\ in\ the\ cylindrical\ vessel +Amount\ of\ water\ in\ conical\ vessel$

$Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi +200\pi \\Now,\\Let\ the\ final\ height\ be\ h_2\\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=\pi *10^2*h_2=100h_2\pi \\Hence,\\100h_2\pi =100h_1\pi +200\pi \\Hence,\\100h_2=100h_1+200\\100h_2-100h_1=200\\100(h_2-h_1)=200\\h_2-h_1=2\\Hence,\\As\ the\ rise\ in\ level\ is\ the\ difference\ between\ the\ initial\ and\ final\\ heights:\\The\ rise\ in\ level\ of\ water=2\ cm$

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2 years ago

Consider the equation below. log_4( x + 3 )= log_2 (2 + x ) Which system of equations can represent the equation?

DaniilM [7]

Answer:

4^y = x + 3

2^y = x + 2

Step-by-step explanation:

log_4(x + 3 ) = log_2 (2 + x )

log_4( x + 3 ) = y

log_2 (2 + x ) = y

4^y = x + 3

2^y = x + 2

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2 years ago

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