All categories

3 years ago

20. Jane and Richard each painted about 1/5

Mathematics

1 answer:

Tatiana [17]3 years ago

3 0

Answer:

I can't draw a picture but its possible cuz they painted ABOUT 1/5 of the bird house so Jane could have painted a bit more than 1/5 but it would still be about 1/5

You might be interested in

A dartboard has a circumference of 78.5 in.What is the diameter?

satela [25.4K]

$2 \pi r = circumference$
so,
$\frac{circumference}{2 \pi } = radius$

it equals 12.49 or 12.5 depending on rounding

I hope this helps!

4 0

3 years ago

Read 2 more answers

Simplify:2 1/3(4 1/4÷2)

kondor19780726 [428]

Answer:

$4\frac{23}{24}$

Step-by-step explanation:

We want to simplify:

$2\frac{1}{3}(4\frac{1}{4}\div 2)$

We convert to improper fraction to get:

$\frac{7}{3}(\frac{17}{4}\div 2)$

We now deal with the parenthesis by multiplying with the reciprocal of 2.

$\frac{7}{3}(\frac{17}{4}\times \frac{1}{2} )$

This gives:

$\frac{7}{3}(\frac{17}{8})$

We multiply to get:

$\frac{7}{3}(\frac{17}{8})$

This simplfies to:

$\frac{119}{24}$

We write as mixed number

$4\frac{23}{24}$

4 0

3 years ago

Which of the following functions is not linear?

Marrrta [24]

Answer:

Step-by-step explanation:

The equation of a linear function is in form:

$y=mx+b$

We have:

$\bold{A.}\\\\y=8(x+8)+4(x+8)\qquad\text{use the distributive property}\\\\y=8x+64+4x+32\qquad\text{combine like terms}\\\\y=12x+86\to m=12,\ b=86\\\\\bold{linear\ function}$

$\bold{B.}\\\\y=\dfrac{\sqrt8}{8}x-4\to m=\dfrac{\sqrt8}{8},\ b=-4\\\\\bold{linear\ function}$

$\bold{C.}\\\\y=\dfrac{1}{8}x+8\to m=\dfrac{1}{8},\ b=8\\\\\bold{linear\ function}$

$\bold{D.}\\\\y=8x^2+8x+4\\\\\bold{not\ linear\ function}\\\\\text{because is}\ x^2\\\\\text{It's a quadratic function}$

3 0

3 years ago

Please help me with this!!

Naddik [55]

Step-by-step explanation:

To find the y-coordinate points we need to evaluate the function for all the $x$ values in the table. In other words, we need to replace $x$ with each value in our given function and simplify.

- For x = 0

$f(x)=(x-2)^2-5$

$f(0)=(0-2)^2-5$

$f(0)=(-2)^2-5$

$f(0)=4-5$

$f(x)=-1$

Since $x=0$ and $y=-1$ , our first point is (0, -1)

- For x = 1

$f(x)=(x-2)^2-5$

$f(1)=(1-2)^2-5$

$f(1)=(-1)^2-5$

$f(1)=1-5$

$f(x)=-4$

Our second point is (1, -4)

- For x = 2

$f(x)=(x-2)^2-5$

$f(2)=(2-2)^2-5$

$f(2)=(0)^2-5$

$f(x)=-5$

Our third point is (2, -5)

- For x = 3

$f(x)=(x-2)^2-5$

$f(3)=(3-2)^2-5$

$f(3)=(1)^2-5$

$f(3)=1-5$

$f(x)=-4$

Our fourth point is (3, -4)

- For x = 4

$f(x)=(x-2)^2-5$

$f(4)=(4-2)^2-5$

$f(4)=(2)^2-5$

$f(4)=4-5$

$f(x)=-1$

Our fifth point is (4, -1)

Now we just need to plot each point in our coordinate plane and join them with the parabola as you can see in the attached picture.

3 0

3 years ago

nu is designing a rectangular sandbox. the bottom is 16 square feet. which dimensions require the least amount of material for t

SCORPION-xisa [38]

Answer:

The least amount of dimensions would be using a 4ft x 4ft base.

Step-by-step explanation:

When looking to maximize area and minimize materials, a perfect square always does this. To prove the point, consider the 4 x 4 box in the answer to say a 16 x 1 box, which would have the same area.

The 4 x 4 box would have 4 sides each of 4 ft. Therefore, it would have 16 feet of sides to construct.

Meanwhile, there would be two sides on the other one that were 16 ft alone.

3 0

3 years ago