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3 years ago

12

AREA OF COMPOSITE SHAPES SOMEONE PLEASE HELP ASAP

1 answer:

gtnhenbr [62]3 years ago

7 0

Answer:

Step-by-step explanation:

Up - 8

Down - 8

⨆

8•8=64

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X − 5 = 17<br> A) x = 22 <br> B) x = 12 <br> C) x = 3.4 <br> D) x = -12

Maksim231197 [3]

A is the correct answer coz if you substitute 22 in the place of X-5 the answer will be 17

8 0

3 years ago

What is the area of rectangle ABCD?<br> A)12<br> B)14<br> C)16<br> D)18

blagie [28]

Answer:12

Step-by-step explanation:

4 by 3

so 4x3=12

4 0

2 years ago

Read 2 more answers

I’m confused can ya help me

Harlamova29_29 [7]

Answer:

C & D

Step-by-step explanation:

x² + 3x - 3 = 0

a = co efficient of x² = 1

b= co efficient of x = 3

c = constant = -3

roots = (-b ± $\sqrt{b-4ac}$ )/2a

= (-3± $\sqrt{3^{2}-4*1*[-3]}$ )/2*1

= (-3± $\sqrt{9+12}$ )/2

= (-3±√21)/2

$x = \frac{-3+\sqrt{21}}{2} ; x =\frac{-3-\sqrt{21}}{2}$

7 0

3 years ago

The radius of a truck wheel is 3 ft. what is the approximate circumference if the truck wheel.

Phoenix [80]

Circumference = $2 \pi r$
When you plug that in you should have $(2* \pi ) *3$
Solve that and you have your answer(: I would recommend rounding to the nearest hundreth

8 0

3 years ago

Read 2 more answers

A rectangular box with a square base is to be constructed from material that costs $9 per ft2 for the bottom, $5 per ft2 for the

kramer

Answer:

$18.73ft^3$

Step-by-step explanation:

Let

Side of square base=x

Height of rectangular box=y

Area of square base=Area of top= $(side)^2=x^2$

Area of one side face= $l\times b=xy$

Cost of bottom=$9 per square ft

Cost of top=$5 square ft

Cost of sides=$4 per square ft

Total cost=$204

Volume of rectangular box= $V=lbh=x^2y$

Total cost= $9(x^2)+5x^2+4(4xy)=14x^2+16xy$

$204=14x^2+16xy$

$204-14x^2=16xy$

$y=\frac{204-14x^2}{16x}=\frac{102-7x^2}{8x}$

Substitute the values of y

$V(x)=x^2\times \frac{102-7x^2}{8x}=\frac{1}{8}(102x-7x^3)$

Differentiate w.r.t x

$V'(x)=\frac{1}{8}(102-21x^2)=0$

$V'(x)=0$

$\frac{1}{8}(102-21x^2)=0$

$102-21x^2=0$

$102=21x^2$

$x^2=\frac{102}{21}=4.85$

$x=\sqrt{4.85}=2.2$

It takes positive because side length cannot be negative.

Again differentiate w.r. t x

$V''(x)=\frac{1}{8}(-42x)$

Substitute the value

$V''(2.2)=-\frac{42}{8}(2.2)=-11.55$

Hence, the volume of box is maximum at x=2.2 ft

Substitute the value of x

$y=\frac{102-7(2.2)^2}{8(2.2)}=3.87 ft$

Greatest volume of box= $x^2y=(2.2)^2\times 3.87=18.73 ft^3$

5 0

3 years ago