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olya-2409 [2.1K]
3 years ago
5

Please help meh T^T Which of the following describes an application error? Select 2 options.

Computers and Technology
2 answers:
Lena [83]3 years ago
8 0

Answer:

"Every time you try to run your new game, it crashes after displaying the opening screen"

"After a recent Windows update, you can no longer access the internet on your laptop"

Explanation:

BartSMP [9]3 years ago
3 0
Answer: 4 and 6 those are right
You might be interested in
Write a program that reads numbers from a file (or allow user to input data) and creates an ordered binary tree. The program sho
IgorLugansk [536]

Answer:

See explaination

Explanation:

include<bits/stdc++.h>

using namespace std;

typedef struct Node

{

int data;

struct Node *left,*right;

}Node;

bool search(Node *root,int data)

{

if(root==NULL)

return false;

if(root->data==data)

return true;

queue<Node*> q;

q.push(root);

while(!q.empty())

{

Node *temp=q.front();

q.pop();

if(temp->data==data)

return true;

if(temp->left)

q.push(temp->left);

if(temp->right)

q.push(temp->right);

}

return false;

}

Node *insert(Node *root,int data)

{

if(root==NULL)

{

Node *temp=new Node();

temp->data=data;

temp->left=NULL;

temp->right=NULL;

return temp;

}

if(data < root->data)

root->left=insert(root->left,data);

if(data>root->data)

root->right=insert(root->right,data);

return root;

}

Node *get_smallest_element_right_subtree(Node *root)

{

while(root && root->left!=NULL)

root=root->left;

return root;

}

Node *delete_node(Node *root,int data)

{

if(root==NULL)

return root;

if(data < root->data)

root->left=delete_node(root->left,data);

else if(data > root->data)

root->right=delete_node(root->right,data);

else

{

if(root->left==NULL) //If right only presents means - delete the curr node and return right node

{

Node *temp=root->right;

free(root);

return temp;

}

else if(root->right==NULL) //If left only presents means - delete the curr node and return let node

{

Node *temp=root->left;

free(root);

return temp;

}

else

{

Node *temp=get_smallest_element_right_subtree(root->right);

root->data=temp->data;

root->right=delete_node(root->right,temp->data);

}

return root;

}

}

void inorder(Node *root)

{

if(root!=NULL)

{

inorder(root->left);

cout<<root->data<<" ";

inorder(root->right);

}

}

void postorder(Node *root)

{

if(root!=NULL)

{

inorder(root->left);

inorder(root->right);

cout<<root->data<<" ";

}

}

void preorder(Node *root)

{

if(root!=NULL)

{

cout<<root->data<<" ";

inorder(root->left);

inorder(root->right);

}

}

int main()

{

fstream f;

string filename;

cout<<"\n\n1 - Input through File ";

cout<<"\n\n2 - Input through your Hand";

int h;

cout<<"\n\n\nEnter Your Choice : ";

cin>>h;

Node *root=NULL; // Tree Declaration

if(h==1)

{

cout<<"\n\nEnter the Input File Name : ";

cin>>filename;

f.open(filename.c_str());

if(!f)

cout<<"\n\nError in Opening a file !";

else

{

cout<<"\n\nFile is Being Read ........";

string num;

int value;

int node=0;

while(f>> num)

{

value=stoi(num);

root=insert(root,value);

node++;

}

cout<<"\n\nTree has been successfully created with : "<<node<<" Nodes"<<endl;

}

}

if(h==2)

{

int y;

cout<<"\n\nEnter the Total No of Input :";

cin>>y;

int i=1,g;

while(i!=y+1)

{

cout<<"\n\nEnter Input "<<i<<" : ";

cin>>g;

root=insert(root,g);

i++;

}

cout<<"\n\nTree has been successfully created with : "<<y<<" Nodes"<<endl;

}

if(h>=3)

{

cout<<"\n\nInvalid Choice !!! ";

return 0;

}

int n=0;

while(n!=6)

{

cout<<"\n\n\n1 - Insert Element";

cout<<"\n\n2 - Remove Element";

cout<<"\n\n3 - Inorder (LNR) Display ";

cout<<"\n\n4 - Pre (NLR) Order Display";

cout<<"\n\n5 - Post (LRN) Order Display";

cout<<"\n\n6 - Quit";

cout<<"\n\nEnter Your Choice : ";

cin>>n;

switch(n)

{

case 1:

{

int k;

cout<<"\n\nEnter Element to insert : ";cin>>k;

root=insert(root,k);

cout<<"\n\nElement Sucessfully Inserted !!!!!";

break;

}

case 2:

{

int k;

cout<<"\n\nEnter Element to Remove : ";

cin>>k;

if(search(root,k))

{

root=delete_node(root,k);

cout<<"\n\nValue Successfully Deleted !!!";

}

else

cout<<"\n\n!!!!!!!!!!!!!!!!!!!! No Such Element !!!!!!!!!!!!!!!!!!!!!!";

break;

}

case 3:

{

cout<<"\n\nThe Elements (LNR) are : ";

inorder(root);

break;

}

case 4:

{

cout<<"\n\nThe Elements (NLR) are : ";

preorder(root);

break;

}

case 5:

{

cout<<"\n\nThe Elements (LRN) are : ";

postorder(root);

break;

}

case 6:

{

break;

}

}

}

cout<<"\n\nBye!!!! See You !!!"<<endl;

7 0
4 years ago
Maria is comparing her history project's second-place award to her classmate's first-place award. She starts planning how to win
weeeeeb [17]

Answer:

i would say long term

Explanation:

if she is planning for a while on how she is gonna get the first place award and its a long period of time before the next history project i would go with long term

5 0
3 years ago
Read 2 more answers
True or False
anastassius [24]

I used this from a other.

False

Software is the collection of large program or instruction of codes, which is used to perform some task. It is of two types of system software and application software.

The system software is used as a container for the application software and it is used to handle all other software it is used to operate the system.

Application software is used to perform any operation. This type of software can be used by the user if it is installed on the local machine on any system software

The operating system is also the part of the system software because it is used to operate the system and it is also the soul of the computer system which is also the function of the system software but the above question states that the operating system is not the part of the system software which is not correct. Hence false is the correct answer to the above question.

5 0
3 years ago
Mattias's friend asked him to critique his presentation about gorillas. Mattias noticed that there weren't any images of gorilla
Deffense [45]

Answer:

c

Explanation:

7 0
3 years ago
In java write a program:A contact list is a place where you can store a specific contact with other associated information such
BigorU [14]

Answer:

import java.util.Scanner;

public class ContactInformation

{

public static String GetPhoneNumber(String[] nameVec, String[] phoneNumberVec, String contactName, int arraySize)  

{  

for(int i=0;i<arraySize;i++)

{

if(nameVec[i].equals(contactName))  

return phoneNumberVec[i];

}  

return "Contact doesn't exists!";

}

public static void main(String[] args)

{

int records;

Scanner sc = new Scanner(System.in);

System.out.print("Enter the size of contact List :");

records=sc.nextInt();

String[] contactNameList=new String[records];

String[] phoneNumberList=new String[records];

String contactName;

System.out.println("Enter the contact name and phone number :");

for(int i=0;i<contactNameList.length;i++)

{  

contactNameList[i]=sc.next();  

phoneNumberList[i]=sc.next();  

}  

System.out.println("Enter the name of the contact to be searched :");  

contactName=sc.next();

System.out.println(GetPhoneNumber(contactNameList,phoneNumberList,contactName,records));  

}  

}

Explanation:

In the following the function defined above for getting the contact

number on the basis of contact number provided we are checking the contact name list if we are able to find the contact name and if we did we return the contact number on the same index from the contact number list

which we found in the contact name list.

4 0
3 years ago
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