Answer:
a. Utilization = 0.00039
b. Throughput = 50Kbps
Explanation:
<u>Given Data:</u>
Packet Size = L = 1kb = 8000 bits
Transmission Rate = R = 1 Gbps = 1 x 10⁹ bps
RTT = 20 msec
<u>To Find </u>
a. Sender Utilization = ?
b. Throughput = ?
Solution
a. Sender Utilization
<u>As Given </u>
Packet Size = L = 8000 bits
Transmission Rate = R = 1 Gbps = 1 x 10⁹ bps
Transmission Time = L/R = 8000 bits / 1 x 10⁹ bps = 8 micro-sec
Utilization = Transmission Time / RTT + Transmission Time
= 8 micro-sec/ 20 msec + 8 micro-sec
= 0.008 sec/ 20.008 sec
Utilization = 0.00039
b. Throughput
<u>As Given </u>
Packet Size = 1kb
RTT = 20ms = 20/100 sec = 0.02 sec
So,
Throughput = Packet Size/RTT = 1kb /0.02 = 50 kbps
So, the system has 50 kbps throughput over 1 Gbps Link.
Based on the information given, it is important to give higher priority to the queue that contains the high priority thread.
<h3>
</h3><h3>
What is the Important Fact?</h3>
- A lot of interrupts can take place at any time, and due to that, they cannot always be ignored as the part of code affected by interrupts need to be guarded from constant use.
- So, the load-balancing requirements for keeping about the same number of threads would need to be taken or retained and the important case of top priority thread would also be kept.
- An priority-based scheduling algorithm can handle this situation if one run queue had all high-priority threads and a second queue had all low-priority threads because if giving greater priority to the two queue that has the national priority comment section as well as, so, first method is the thread in all of the queue.
- Multi-level queue scheduling algorithm is used in scenarios where the processes can be classified into groups based on property like process type, CPU time, IO access, memory size, etc. One general classification of the processes is foreground processes and background processes.
To learn more about multi-level refer to:
brainly.com/question/16902508
#SPJ4
Answer:
Please see the full code in explanation
Explanation:
#This is a console program
def bill_calculator():
print("Enter the Total value of the bill:\n")
bill_total = float(input())
print("Enter total number of dinners:\n")
total_dinner = int(input())
bill_per_person = bill_total / total_dinner
result = ("Bill total: {} \n"
"Total dinners: {} \n"
"Bill per person: {} ").format(bill_total,total_dinner, bill_per_person)
print(result)
if __name__ == '__main__':
bill_calculator()
Answer:
for i in range
Explanation:
This is the only excerpt of code
A(n) -input- is a named storage location that can hold a data value.
