Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
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now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
it is 3 divided by 31 then subtract 31 with 30 which will give you 10R1
Answer:
SI = 2052.61 ft
Step-by-step explanation:
cos 13 = 2000/SI
0.9744 = 2000/SI
multiply both sides by SI:
(SI)(0.9744) = 2000
divide both sides by 0.9744:
SI = 2052.61 ft