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tino4ka555 [31]

2 years ago

14

Egan is very skilled at budgeting his money, he is very patient, he understands how to track his own financial records, and he k

eeps calm and collected during stressful occasions. In which Finance career would Egan be most successful?
Business Finance Management

Financial Investment Planning

Insurance Services

Banking and Related Services

2 answers:

erastovalidia [21]2 years ago

4 0

Answer:

A) Business Finance Management

Explanation:

just took the test

pentagon [3]2 years ago

3 0

Answer:

Business Finance Management

Explanation:

Business Finance Management is the best fit for this because of requires a lot of skill in planning and budgeting money.

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John Roberts is 55 years old and has been asked to accept early retirement from his company. The company has offered John three

MArishka [77]

Answer:

Answer is on the chegg link i provided

Explanation:

https://www.chegg.com/homework-help/john-roberts-55-years-old-asked-accept-early-retirement-comp-chapter-6-problem-9p-solution-9780078025327-exc

5 0

3 years ago

Donovan Company incurred the following costs while producing 500 units: direct materials $10 per unit, direct labour $25 per uni

Dafna1 [17]

Answer:

Option (D) is correct.

Explanation:

Unit product cost:

= Direct materials + Direct labor + Variable manufacturing overhead + Fixed manufacturing overhead

= $10 + $25 + $15 + $20

= $70

Operating income using absorption costing:

= (500 units × $100) - (500 units × $70) - (500 units × $5) - $7,500

= $50,000 - $35,000 - $2,500 - $7,500

= $5,000

8 0

3 years ago

Tirri Corporation has provided the following information: Cost per UnitCost per PeriodDirect materials$ 7.05 Direct labor$ 4.20

Kazeer [188]

Answer:

Contribution margin per unit= $12.85

Explanation:

Giving the following information:

Direct materials$ 7.05

Direct labor$ 4.20

Variable manufacturing overhead$ 1.55

Sales commissions $ 1.15

Variable administrative expense$ 0.40

<u>To calculate the contribution margin, we need to use the following formula:</u>

Contribution margin per unit= selling price - total unitary variable cost

Contribution margin per unit= 27.2 - (7.05 + 4.2 + 1.55 + 1.15 + 0.4)

Contribution margin per unit= $12.85

8 0

2 years ago

Concord Corporation planned to use 1 yard of plastic per unit budgeted at $91 a yard. However, the plastic actually cost $90 per

Greeley [361]

Answer:

Total Material Variance = $10,060 Unfavorable

Explanation:

Provided Information,

Standard budgeted unit of raw material = 1 yard

Standard price per unit = $91.00

Actual price per yard = $91.00

Actual units produced = 4,600

Actual yards of plastic used = 4,660 yards

Standard yards for actual production = 4,600 $\times$ 1 yard = 4,600

Total Material Variance = Standard Cost for actual output - Actual Cost

Standard Cost = 4,600 $\times$ $90 = $414,000

Actual Cost = 4,660 $\times$ $91 = $424,060

Total Material Variance = $414,000 - $424,060 = - $10,060

Since value is negative as actual cost is more than budgeted, the variance is unfavorable.

Final Answer

Total Material Variance = $10,060 Unfavorable

8 0

3 years ago

Pressure with Two Liquids, Hg and Water. An open test tube at 293 K is filled at the bottom with 12.1 cm of Hg, and 5.6 cm of wa

Radda [10]

Answer:

$1170839.28 dyn/cm^2$

16.9816 psia

$117.083928 kN/m^2$

Explanation:

To calculate the absolute pressure in the bottom of tube we need to sum the atmosferic and gauge pressure.

$P_{abs}=P_{atm}+P_G$

And the gauge pressure is given by the contributions of columns of water ( $P_{w}$ ) and mercury( $P_{Hg}$ ), we can calculate the contribution of each column as:

$P= \rho g h$ (*)

where $\rho$ is the respective density, g gravity and h is height.

So we have all the data required to use the above equations ( $P_{atm}$ , height and density of each column) we only need to be carefully with the units.

For simplicity we can to express all pressure contributions in mmHg ( $P_{atm}$ , $P_{w}$ and $P_{Hg}$ ). Note that the units "x" mmHg means the pressure at the bottom of a column of mercury of "x" mm high. For example, in this case we have a column 12.1 cm of Hg, that is a column of 121 mmHg (passing from cm to mm only requires multiply by 10) pressure exerted by that column is 121 mmHg.

Now pressure of 5.6 cm (56 mm) of water would be 56 mm of water, but it is not the same that mmHg, since the density of water is lower, the pressure exerted by 1 mm of water is lower than the exerted by 1 mm of Hg. The conversion between mmHg and mm of water is given by the relation between the densities.

$mmHg=\frac{\rho_w*mmH_2O}{\rho_{Hg}}$

$mmHg=\frac{0.998*mmH_2O}{13.55}=0.0737 mmH_2O$

And pressure of water in mmHg is

$0.0737*56=4.1246 mmHg$

The absolute pressure is:

$P_{abs}=P_{atm}+P_G= 756 + 121 + 4.1246 = 881.1246 mmHg = 88.11246cmHg$

To pass to dyn/cm^2 units we need to use the equation (*)

$P= \rho g h = 13.55 \frac{g}{cm^3} * 980.665 \frac{cm}{s^2} * 88.11246 cmHg = 1170839.28 \frac{g}{cm s^2} = 1170839.28 \frac{dyn}{cm^2}$

Note: We need to use cm Hg for units coherence

Now passing from dyn/ $cm^2$ to kN/ $m^2$ (or kPa) we need to consider that 1 dyn is $10^{-8}$ kN and 1 $cm^2$ is $10^{-4} m^2$ .

$1170839.28 \frac{dyn}{cm^2} * \frac{10^{-8}kN}{1 dyn}*\frac{cm^2}{10^{-4}m^2}=117.083928kN/m^2$

Now passing kN/ $m^2$ to psia. We need to consider that 1 psia is 6.89476.

$117.083928kN/m^2*\frac{1psia}{6.89476kN/m^2}=16.9816 psia$

8 0

3 years ago